The recommended density of a rectangular aquarium is 7 fish per cubic foot of water. If the owner of the aquarium follows the re
commended density guidlines and has 42 fish, what is the height of the aquaruim with a length of 3 feet and a width of 1 foot?
1 answer:
Answer: 2 feets
Step-by-step explanation:
Recommended density = 7 fish/ ft^3
If recommended density guideline is followed:
Number of fishes in aquarium = 42
Length of aquarium = 3ft
Width = 1ft
Height =?
Volume of aquarium = Length × width × height
Volume = 3 × 1 × h = (3ft^2 × h)
Therefore ;
If
1ft^3 = 7 fishes
x ft^3 = 42 fishes
Cross multiply
7(x)ft^3 = 42 fishes
x ft^3 = (42÷7)
x ft^3 = 6
Therefore volume of the aquarium with 42 fishes is 6ft^3
Volume = (3ft^2 × h)
6ft^3 = 3ft^2 × h
h = (6ft^3) / (3ft^2)
h = 2ft
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