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Lady_Fox [76]
3 years ago
9

Someone please help me

Mathematics
1 answer:
tester [92]3 years ago
6 0
I believe the answer is 8, I am sorry if I am wrong. Hope this helps and have a good day.
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What is the are of the shaded sector? Please help
Schach [20]

Answer:

339.2925‬

Step-by-step explanation:

4 0
3 years ago
Taisha uses the elliptical cross- trainer at the gym. Her general goal is to burn 280 calories per workout, but she varies by as
Fed [463]

Given - Taisha has a general goal is to burn the 280 calories.

she is varies by the 25 calories.

Find out the maximum and minimum of calories burn by the taisha.

To proof -

let us assume that the calories burn by the taisha be x.

as given the calories are varies by the 25 calories.

then the maximum calories equation becomes

x-25 = 280

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minimum calories equationbecomes

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8 0
3 years ago
Read 2 more answers
Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%. Find
Papessa [141]

Answer:

1) \text{P(at least one boy and one girl)}=\frac{3}{4}

2) \text{P(at least one boy and one girl)}=\frac{3}{8}

3) \text{P(at least two girls)}=\frac{1}{2}

Step-by-step explanation:

Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.

To  Find : The probability of each event.  

1) P(at least one boy and one girl)

2) P(two boys and one girl)

3) P(at least two girls)        

Solution :

Let's represent a boy with B and a girl with G

Mr. and Mrs. Romero are expecting triplets.

The possibility of having triplet is

BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG

Total outcome = 8

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

1) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, BGG, GBB, GBG, GGB=6

\text{P(at least one boy and one girl)}=\frac{6}{8}

\text{P(at least one boy and one girl)}=\frac{3}{4}

2) P(at least one boy and one girl)

Favorable outcome =  BBG, BGB, GBB=3

\text{P(at least one boy and one girl)}=\frac{3}{8}

3) P(at least two girls)

Favorable outcome = BGG, GBG, GGB, GGG=4

\text{P(at least two girls)}=\frac{4}{8}

\text{P(at least two girls)}=\frac{1}{2}

4 0
4 years ago
Read 2 more answers
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DiKsa [7]
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How do I write 6 x 3/20 as a fraction in simplest form?
Talja [164]
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