Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer:
what does that question mean?
First we convert feet into meters, since 1 feet is 0.3048 m: 275 feet * 0.3048 = 83.82m.
Then we do: 83.82m / 3.23s = <span>25.9504644 m/s.
Then we convert that into miles per hour by </span>2.23694, so we do:
25.9504644 * 2.23694 = <span>58.0496318.
Then we round it to 58 mph.
So the answer is: The cheetah was running at 58 mph.
Hope this helped! c:</span>
2.6 = 2.600
So, 2.6 is not bigger than 2.661