It makes it alot easier to call out locations and plot them fast.
Answer:
=12
Step-by-step explanation:
Answer:
A and B
Step-by-step explanation:
We are given that
![g(x)=x^2-4x+3](https://tex.z-dn.net/?f=g%28x%29%3Dx%5E2-4x%2B3)
![g(x)=(x^2-2\times x\times 2+4)-4+3=(x-2)^2-1](https://tex.z-dn.net/?f=g%28x%29%3D%28x%5E2-2%5Ctimes%20x%5Ctimes%202%2B4%29-4%2B3%3D%28x-2%29%5E2-1)
Compare with it
![y=(x-h)^2+k](https://tex.z-dn.net/?f=y%3D%28x-h%29%5E2%2Bk)
Where vertex=(h,k)
We get
Vertex of g=(2,-1)
![f(x)=x^2-4x=(x^2-2\times x\times 2+4)-4=(x-2)^2-4](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-4x%3D%28x%5E2-2%5Ctimes%20x%5Ctimes%202%2B4%29-4%3D%28x-2%29%5E2-4)
Vertex of f=(2,-4)
Equation of axis of symmetry=x-coordinate of vertex
Axis of symmetry of g
x=2
Axis of symmetry of f
x=2
Differentiate w.r.t x
![g'(x)=2x-4=0](https://tex.z-dn.net/?f=g%27%28x%29%3D2x-4%3D0)
![2x-4=0\implies 2x=4](https://tex.z-dn.net/?f=2x-4%3D0%5Cimplies%202x%3D4)
![x=\frac{4}{2}=2](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7B2%7D%3D2)
![f'(x)=2x-4](https://tex.z-dn.net/?f=f%27%28x%29%3D2x-4)
![2x-4=0\implies 2x=4](https://tex.z-dn.net/?f=2x-4%3D0%5Cimplies%202x%3D4)
![x=\frac{4}{2}=2](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7B2%7D%3D2)
![g''(x)=2>0](https://tex.z-dn.net/?f=g%27%27%28x%29%3D2%3E0)
![f''(x)=2>0](https://tex.z-dn.net/?f=f%27%27%28x%29%3D2%3E0)
f and g have both minima at x=2
Hence, option A and B are true.
Answer:
What’s the question?
Step-by-step explanation:
Answer:
x=57
Step-by-step explanation:
3x-8=163
3x=171
x=57