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Mashcka [7]
3 years ago
5

One day at St. Philip's High School, 1/2 of the pupils walked to school, 1/5 of the pupils came to school by bus, and the remai

ning 57 pupils came by car. so then How many pupils are there in the school?
Mathematics
1 answer:
Doss [256]3 years ago
7 0
Let P be the number of kids,
we know P>57
take 1-(1/2)-(1/5)=3/10
therefore 57 is 3/10P
3/7P=57
P=57*7/3=133 is the answer
it would be incorrect if we didnt get a positive integer.
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The table represents the speed of Frog A at a frog-jumping contest. Frog B travels 2 feet each second. If the course is 20 feet
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Step-by-step explanation:

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a lamp post cast a Shadow 15 feet long while a 6 foot man standing nearby cast a shadow 5 ft long. what proportion can be used t
kolezko [41]

Answer:

6/5=x/15

Step-by-step explanation:

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A letter is selected at random from each of the words, Sure and WIN. Find
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Jimmy's backyard is rectangle that is 18 5/6 yards long and 10 2/5 yards wide Jim buy sod in pieces that are 1 1/3 yard long and
g100num [7]

Answer:

111 pieces of soda

Step-by-step explanation:

step 1

Find the area of the rectangular backyard

The area of the rectangular backyard is equal to

A=LW

where

L=18\frac{5}{6}\ yd=\frac{18*6+5}{6}=\frac{113}{6}\ yd

W=10\frac{2}{5}\ yd=\frac{10*5+2}{5}=\frac{52}{5}\ yd

substitute

A=(\frac{113}{6})(\frac{52}{5})

A=\frac{5,876}{30}\ yd^2

step 2

Find the area of one piece of sod

The area of the rectangular piece of sod is

A=LW

where

L=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd

W=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd

substitute

A=(\frac{4}{3})^2\\\\A=\frac{16}{9}\ yd^2

step 3

Find the pieces of sod needed

To find out how many whole pieces of sod will Jim need to buy to cover his backyard, divide the area of the backyard by the area of one piece of soda

so

\frac{5,876}{30} : \frac{16}{9}=\frac{52,884}{480}=110.175

Round up

111 pieces of soda

8 0
3 years ago
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