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Rzqust [24]
3 years ago
7

The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation

of 7°F, what percentage of the time would the temperature be between 55°F and 76°F?
Mathematics
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = \mu = 69

Standard deviation = \sigma = 7

Formula : z=\frac{x-\mu}{\sigma}

Now At x = 55

z=\frac{55-69}{7}

z=-2

At x = 76

z=\frac{76-69}{7}

z=1

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = 0.8185 \times 100 = 81.85\%

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

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