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juin [17]
3 years ago
15

Can someone help me?

Mathematics
1 answer:
Tresset [83]3 years ago
6 0
Question 2 use 180 -115 and divide by 2

maybe
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5x6-1+3=28 brackets or braces should be added
Artyom0805 [142]
5 · (6 - 1) + 3
= 5·5 + 3
= 25 + 3
= 28
7 0
3 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find the length of the angle bisector of an
nordsb [41]

Check the picture below.

bearing in mind that an angle bisector segment will cut the angle A in two equal halves, thus θ will be half of A.

6 0
3 years ago
Solving quadratic equations solve: x^2=81
xenn [34]

Answer:9

Step-by-step explanation:

Square root of 81 is9.

8 0
3 years ago
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Adding fractions with unlike denominators<br>​
insens350 [35]

Answer:

A

Step-by-step explanation:

6 0
2 years ago
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Find the compound interest on Rs. 2000 for one year at the rate of '20%' per annum. If theinterest compounded quarterly.​
trasher [3.6K]

Given:

Principal = Rs. 2000

Rate of interest = 20% p.a. compounded quarterly.

Time = 1 year

To find:

The compound interest.

Solution:

Formula for amount:

A=P\left (1+\dfrac{r}{n}\right)^{nt}

where,

P = Principal

r = Rate of interest

t= Time

n = number of times interest compounded in an year.

Putting P=2000, r=0.2, n=4 and t=1, we get

A=2000\left (1+\dfrac{0.2}{4}\right)^{4(1)}

A=2000\left (1.05\right)^{4}

A=2000\left (1.21550625\right)

A=2431.0125

Now, the compound interest is

C.I.=A-P

C.I.=2431.0125-2000

C.I.=431.0125

Therefore, the compound interest is Rs 431.0125.

3 0
3 years ago
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