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frutty [35]
3 years ago
14

Anyone know how to solve?

Mathematics
1 answer:
Julli [10]3 years ago
3 0
13. 72 + 72 + X = 180
X = 180 - 144
X = 36
angle A= 36

14. X + X + 101 = 180
X+X =180-101
X+X= 79 divided by 2
X= 39.5
angle B= 39.5

Plz mark as brainleast plzzz
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Answer:

6p + 4d = 36

Step-by-step explanation:

If p = number of pins and d = number of major decisions, then the equation is 6p + 4d = 36.

Hope this helps!

5 0
3 years ago
Evaluate each expression for g = -7 and h = 3 and match it to its value.
Arturiano [62]

Answer:

The values of given expressions are:

1. gh = -21

2. g^2 - h = 46

3. g + h^2 = 2

4. g + h  = -4

5. h - g  = 10

6. g - h = -10

Step-by-step explanation:

Given values of g and h are:

g = -7

h = 3

<u>1. gh</u>

The two numbers are being multiplied

Putting the values

gh = (-7)(3) = -21

<u>2. g^2-h</u>

Putting the values

=(-7)^2-3\\=49-3\\=46

<u>3. g+h^2</u>

Putting the values

= -7 + (3)^2\\=-7+9\\=2

<u>4. g+h</u>

Putting the values

= -7+3\\=-4

<u>5. h-g</u>

Putting the values

= 3 - (-7)\\=3+7\\=10

<u>6. g-h</u>

Putting values

=-7-3\\=-10

Hence,

The values of given expressions are:

1. gh = -21

2. g^2 - h = 46

3. g + h^2 = 2

4. g + h  = -4

5. h - g  = 10

6. g - h = -10

4 0
3 years ago
Read 2 more answers
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3 years ago
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car?
Ghella [55]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
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