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tatiyna
2 years ago
10

2. Mrs. Jones' science class is planting sunflowers in the school garden. Her class

Mathematics
1 answer:
Levart [38]2 years ago
6 0

Answer:

1 sunflower

Step-by-step explanation:

Start at 15 then go to the left of the line graph. After count how many X there are which there is one.

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Find the regular price. Round to the nearest cent . Sales price is 56.78 percent discount is 40%
LenaWriter [7]

100\%-40\%=60\%\\60\% = \frac{60}{100}=\frac{6}{10}=\frac{3}{5}\\\\

Numerator is 3 and denominator is 5. So, we divide the sales price by 3 and we multiply by 5 to get the whole fraction, or 100%.

\frac{56.78*5}{3} \\\frac{283.9}{3} \\94.6333333333333...

Your regular price sounds recurring, so you might have made a mistake copying.

The answer for what you've got is 94.633333...

5 0
2 years ago
Eight time the difference of a number and nice
kirza4 [7]

Answer:

8 (x -9)

Step-by-step explanation:

I don't know if you ment 9 instead of 9, but if you did that that would be the answer!

7 0
3 years ago
16+5x=8x-5 What would the variable be?
11111nata11111 [884]
16+5x =8x-5

Reorder the terms
16+5x = -5+8x
Solving for variable for x

Move all terms containing x to the left, all other terms to the right.
Add -8x to each side of the equation.
16+ -3x = -5 + 8x + -8x

Combine like terms: 5x + -8x=-3x
16+-3x = -5 + 8x + -8x

Combine like terms: 8x + -8x = 0
16+-3x = -5 + 0
16+ -3x = -5

Add -16 to each side of the equation
16+-16 + -3x = -5 + 16

Combine like terms: 16+ -16 = 0
0 + -3x =-5 + -16
-3x = -5 + -16

combine like terms: -5 + -16 = -21
-3x = -21
Divide each side by -3
x=7


7 0
3 years ago
The mr William two questions please!
melamori03 [73]

well, in short, the students and chaperones are at a 2 : 9 ratio, and we know there are 171 students, how many chaperones then, so long they maintain a 2:9 ratio?

\bf \cfrac{chaperones}{students}\qquad 2:9\qquad \cfrac{2}{9}\qquad \qquad \cfrac{x}{171}=\cfrac{2}{9}\implies 9x=2(171) \\\\\\ 9x=342\implies x=\cfrac{342}{9}\implies x=38

5 0
3 years ago
Fine length of BC on the following photo.
MrMuchimi

Answer:

BC=4\sqrt{5}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

AC^2=AD^2+DC^2

substitute the given values

AC^2=16^2+8^2

AC^2=320

AC=\sqrt{320}\ units

simplify

AC=8\sqrt{5}\ units

step 2

In the right triangle ACD

Find the cosine of angle CAD

cos(\angle CAD)=\frac{AD}{AC}

substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

cos(\angle CAD)=\frac{2}{\sqrt{5}} ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

cos(\angle BAC)=\frac{AC}{AB}

substitute the given values

cos(\angle BAC)=\frac{8\sqrt{5}}{16+x} ----> equation B

step 4

Find the value of x

In this problem

\angle CAD=\angle BAC ----> is the same angle

so

equate equation A and equation B

\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}

solve for x

Multiply in cross

(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units

DB=4\ units

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

BC^2=DC^2+DB^2

substitute the given values

BC^2=8^2+4^2

BC^2=80

BC=\sqrt{80}\ units

simplify

BC=4\sqrt{5}\ units

7 0
2 years ago
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