Hey there,
15 games = 7 hits
1 game = 7 / 15
= <span>0.46666666666
45 games = </span><span>0.46666666666 x 45
= 21
Hope this helps :))
<em>~Top♥</em>
</span>
1. Check the drawing of the rhombus ABCD in the picture attached.
2. m(CDA)=60°, and AC and BD be the diagonals and let their intersection point be O.
3. The diagonals:
i) bisect the angles so m(ODC)=60°/2=30°
ii) are perpendicular to each other, so m(DOC)=90°
4. In a right triangle, the length of the side opposite to the 30° angle is half of the hypothenuse, so OC=3 in.
5. By the pythagorean theorem,

6. The 4 triangles formed by the diagonal are congruent, so the area of the rhombus ABCD = 4 Area (triangle DOC)=4*

=

(

)
Answer: See Below
Step-by-step explanation:
Create the equation:
$34 times the number of people plus the $50 cleaning fee has to be less than or equal to $3500
Or
34p + 50 <= 3500
34p <= 3450
p <= 101.470588....
We can have a part of a person attending the reception so we have to drop the remainder/decimal. Therefore the most amount of people that can attend the party and stay within budget is 101.
Answer:
where's the question.........
Answer:
47=4n-3
Step-by-step explanation:
N=11 btw