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Elena-2011 [213]
3 years ago
7

If sea water contains 3.5% of salt. How much seawater do you need in order to get 17.5 lb of salt?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
5 0

Answer:

500 lb

Step-by-step explanation:

Let x lb be the weight of seawater needed to get 17.5 lb of salt.

Now,

x lb - 100%

17.5 lb - 3.5%

Write a proportion:

\dfrac{x}{17.5}=\dfrac{100}{3.5}

Cross multiply:

x\cdot 3.5=100\cdot 17.5\\ \\x=\dfrac{100\cdot 17.5}{3.5}=500\ lb

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4 ftA wire isneeded tosupport averticalpole 4 feettall. Thecable willbeanchoredto a stake3 feet fromthe baseof thepole. How3 ftA
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SOLUTION

From the image in the question, we can see that it is a right triangle problem.

And we can use the Pythagoras theorem to solve for the length of cable wire needed.

Pythagoras theorem states that:

\begin{gathered} \text{hypotenuse}^2=opposite^2+adjacent^2 \\ x^2=4^2+3^2 \end{gathered}\begin{gathered} x^2=16+9 \\ x^2=25 \\ \text{Take the square roots of both sides:} \\ \sqrt[]{x^2}=\sqrt[]{25} \\ x=5ft \end{gathered}

Final Answer:

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5 0
1 year ago
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