If sea water contains 3.5% of salt. How much seawater do you need in order to get 17.5 lb of salt?

Mathematics

1 answer:

CaHeK987 [17]3 years ago

5 0

Answer:

500 lb

Step-by-step explanation:

Let x lb be the weight of seawater needed to get 17.5 lb of salt.

Now,

x lb - 100%

17.5 lb - 3.5%

Write a proportion:

$\dfrac{x}{17.5}=\dfrac{100}{3.5}$

Cross multiply:

$x\cdot 3.5=100\cdot 17.5\\ \\x=\dfrac{100\cdot 17.5}{3.5}=500\ lb$

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