C) Quartile 3 (q3) minus Quartile 1 (q1)
It should be 130 as from day one to day two and to day three it goes up by 10 so 12*10+10
We are given : Distance of the swing = 100 feet.
Distance of slide = 80 feet.
Angle between swing and slide = 30 degrees.
We need to find the distance between the swing and the slide.
Distance of swing, distance of slide and distance between the swing and the slide form a triangle.
We can apply cosine law to find the distance between the swing and the slide.
c^2 = a^2 +b^2 - 2ab cos C
c^2 = 100^2 +80^2 - 2(100)(80) cos 30°
c^2 = 10000 + 6400 -2* 8000
c^2 = 16400 - 8000
c^2 = 16400 - 13856
c^2 = 2544
c= 50.44
c = 50 feet approximately.
<h3>Therefore, the approximate distance between the swing and the slide is 50 feet.</h3>
C(n)=2.00+3.20n
If n = 4 miles:
C(4)=2+3.20(4)
C(4)=2+12.80
C(4)=14.80
The cost of the taxi is $14.80.
Answer:
no
Step-by-step explanation:
no bc 8 is a multiple of 56, not 56 a multiple of 8
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