Twice as much more will the freezing point of water be lowered in beaker a than in beaker b.
<h3>What determines freezing point?</h3>
A liquid's freezing point rises if the intermolecular interactions between its molecules are strong. The freezing point, however, drops if the molecules of inter - molecular are minimal. The process through which a substance transforms from a liquid into a solid is known as freezing.
<h3>How significant is freezing point?</h3>
Freezing points play a big role in occupational safety. A chemical may perhaps turn harmful if held below its freezing point. A critical safety benchmark for assessing the effects of worker exposure to cold environments is the freezing point.
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Answer:
0.4M NaOH
Explanation:
Molarity, M, is an unit of concentration widely used defined as the ratio between moles of solute (In this case, NaOH) and volume of solution in liters.
As the solution contains 2 moles of NaOH-Moles of solute- in 5L of solution, the molarity is:
2 moles NaOH / 5L =
<h3>0.4M NaOH</h3>
Answer:
#Molecules XeF₆ = 2.75 x 10²³ molecules XeF₆.
Explanation:
Given … Excess Xe + 12.9L F₂ @298K & 2.6Atm => ? molecules XeF₆
1. Convert 12.9L 298K & 2.6Atm to STP conditions so 22.4L/mole can be used to determine moles of F₂ used.
=> V(F₂ @ STP) = 12.6L(273K/298K)(2.6Atm/1.0Atm) = 30.7L F₂ @ STP
2. Calculate moles of F₂ used
=> moles F₂ = 30.7L/22.4L/mole = 1.372 mole F₂ used
3. Calculate moles of XeF₆ produced from reaction ratios …
Xe + 3F₂ => XeF₆ => moles of XeF₆ = ⅓(moles F₂) = ⅓(1.372) moles XeF₆ = 0.4572 mole XeF₆
4. Calculate number molecules XeF₆ by multiplying by Avogadro’s Number (6.02 x 10²³ molecules/mole)
=> #Molecules XeF₆ = 0.4572mole(6.02 x 10²³ molecules/mole)
= 2.75 x 10²³ molecules XeF₆.
Answer: Butane will effuse more quickly because it has a smaller molar mass
Explanation:
Molar mass of C4H10 = 58.123 g/mole
Molar mass of I2 = 253.808 g/mole
