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erastovalidia [21]

4 years ago

11

A 56 g sample of peanut oil has a volume of 60.9 cm³. Calculate the density of the peanut oil. Remember to use the correct numbe

r of significant digits in your answer.
Density=____ g/cm3

2 answers:

Ivan4 years ago

5 0

0.92 because Mass divided by Volume = Density

telo118 [61]4 years ago

3 0

The correct answer its:

0.92

hope it helps

can I get the rainliest please?

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Some scientists hypothesize that Earth's ozone layer is being damaged by chlorofluorocarbons .

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For the following reaction, 6.79 grams of hydrogen gas are mixed with excess iodine . The reaction yields 775 grams of hydrogen

horsena [70]

Answer:

$m_{HI}=860gHI\\\\Y=90.1\%$

Explanation:

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In this case, for the reaction:

$H_2+I_2\rightarrow 2HI$

As 6.79 g of hydrogen (molar mass = 2.02 g/mol) react in excess iodine, we can compute the theoretical yield of hydrogen iodide (molar mass = 127.91 g/mol) via their 1:2 mole ratio shown on the chemical reaction:

$m_{HI}=6.79gH_2*\frac{1molH_2}{2.02gH_2}* \frac{2molHI}{1molH_2}*\frac{127.91gHI}{1molHI}\\\\m_{HI}=860gHI$

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$Y=\frac{775g}{860g}*100\%\\\\Y=90.1\%$

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3 years ago

NASA shipped 59,000 grams of water (H2O) to the space station. How many grams of oxygen gas (O2) can theoretically be produced u

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How many moles of Fe are present in 24.6g of the compound

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3 years ago

A solution of 0.133 M KOH is used to titrate 15.0 mL of a H2SO4 solution. Write out the balanced chemical equation and what is t

Korolek [52]

Answer:

The answer to your question is a) H₂SO₄ + 2KOH ⇒ K₂SO₄ + 2H₂O

b) Molarity = 0.127

Explanation:

Data

[KOH] = 0.133 M

volume of KOH = 28.2 ml

[H₂SO₄] = ?

volume of H₂SO₄ = 15 ml

1) Balanced chemical reaction

H₂SO₄ + 2KOH ⇒ K₂SO₄ + 2H₂O

Reactants Elements Products

2 K 2

1 S 1

4 H 4

6 O 6

2) Calculate the molar mass of H₂SO₄ and KOH

H₂SO₄ = (1 x 2) + (32 x 1) + (16 x 4) = 2 + 32 + 64 = 98 g

KOH = (39 x 1) + (16 x 1) + (1 x 1) = 39 + 16 + 1 = 56 g

- Calculate the number of moles of KOH

Molarity = moles / volume

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 0.133 x 28.2/1000

= 0.0038

- Calculate the moles of H₂SO₄

1 mol of H₂SO₄ ------------------ 2 moles of KOH

x ------------------ 0.0038 moles

x = (0.0038 x 1)/2

x = 0.0019 moles of H₂SO₄

-Calculate the molarity of H₂SO₄

Molarity = 0.0019/0.015

Molarity = 0.127

3 0

3 years ago