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erastovalidia [21]
3 years ago
11

A 56 g sample of peanut oil has a volume of 60.9 cm³. Calculate the density of the peanut oil. Remember to use the correct numbe

r of significant digits in your answer.
Density=____ g/cm3
Chemistry
2 answers:
Ivan3 years ago
5 0
0.92 because Mass divided by Volume = Density 
telo118 [61]3 years ago
3 0

The correct answer its:

0.92

hope it helps

can I get the rainliest please?

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Describe the structure of an Atom (HELP!)
Marat540 [252]

Answer:

The answer is A.

Explanation:

Neutrons and protons are located in the dense middle of the atom called the nucleus, and electrons are located on the electron cloud located outside of the nucleus.

4 0
3 years ago
Convert 99 moles of CO2 to atoms
lorasvet [3.4K]

Answer:

              1.78 × 10²⁶ Atoms

Explanation:

Relation between number of molecules and moles is,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 99 mol × 6.022 × 10²³ Molecules/mol

No. of Molecules = 5.96 × 10²⁵ Molecules

Also, In CO₂ Molecule there are 3 atoms.

So,

No. of atoms = 5.96 × 10²⁵ Molecules × 3

No. of atoms = 1.78 × 10²⁶ Atoms

3 0
3 years ago
There is a 30g of be-11 it has a half-life of about 14 seconds how much will be left in 28 seconds
Lelu [443]

There will be 7.5 g of Be-11 remaining after 28 s.

If 14 s = 1 half-life, 28 s = 2 half-lives.

After the first half-life, ½ of the Be-11 (15 g) will disappear, and 15 g will remain.

After the second half-life, ½ of the 15 g (7.5 g) will disappear, and 7.5 g will remain.

In symbols,

<em>N</em> = <em>N</em>₀(½)^<em>n</em>

where

<em>n</em> = the number of half-lives

<em>N</em>₀ = the original amount

<em>N</em> = the amount remaining after <em>n</em> half-lives

6 0
3 years ago
Assume you mixed 5 µl of your cod fish homogenate with 195 µl working solution. The fluorometer displays a measurement of 12.2 µ
11111nata11111 [884]

Answer:

Hallo

Explanation:

I took that question

3 0
3 years ago
1) Given the balance equation below. Calculate how much Na3PO4 in grams you
juin [17]

Answer:

<u>136.67 g of Na3PO4 i</u>s required to create 100 gram of NaOH.

Explanation:

The balanced equation:

Na_{3}PO_{4} + 3 KOH \rightarrow 3 NaOH + K_{3}PO_{4}

1 mole Na3PO4 = 164 g/mole (Molar mass)

1 mole NaOH = 40 g/mole (Molar mass)

Now,

1 mole of Na3PO4 produce = 3 mole of NaOH

164 g/mol of Na3PO4 produce = 3(40) g/mol of NaOH

or

120 g/mol of NaOH is produced from = 164 g/mol of Na3PO4

1 g/mol of NaOH is produced from =

\frac{164}{120}

100 grams of NaOH is produced from =

\frac{164}{120}\times100 gram of Na3PO4

calculate,

= 136.67 g

8 0
3 years ago
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