So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Answer:
A: 3
Step-by-step explanation:
Hopefully this helps!
Answer:
n=1
can you also please mark me as brainliest?
thanks!
Answer:
$50
Step-by-step explanation:
If he pays $10 every month, and he pays for 5 months, it would be 10 x 5, which means he would be $50 in debt.
