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andrew11 [14]
3 years ago
9

Does anyone know the answer to this??? Please help

Mathematics
1 answer:
Mamont248 [21]3 years ago
5 0

Notice that the line b is on adds up 180°.

So, 180 - (45 + 50) = 85

A b = 85°

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How else can the ratio 4/5 be written
Musya8 [376]
4 to 5, or 4.5. I hoped I helped!! 

-Dawn
3 0
3 years ago
Read 2 more answers
The table below shows the total sales by a computer salesman during a three-year period. year 1. $5,000. year 2. $8,500 year 3.
Anastasy [175]

Answer:

3000

Step-by-step explanation:

1312.50+625+1062.5=3000

5 0
3 years ago
A person starts walking from home and walks: 4 miles east 3 miles southeast 3 miles south 4 miles southwest 3 miles east find to
Fantom [35]
A geometry program can show you the total displacement is about 10.14 miles.

_____
You can use a vector calculator to find the solution, too. Using bearing angles, the sum is
   4∠90° + 3∠135° + 3∠180° + 4∠225° + 3∠90° ≈ 10.1390∠141.6354°

_____
If you want to do it by hand, you can recognize the sum will be
   7 miles east + 3 miles south + 3 miles southeast + 4 miles southwest

Distances that are not in the direction of one of the coordinate axes can be translated to rectangular coordinates by 
   displacement*(cos(angle), sin(angle))
Angles can be measured in the conventional way—from the positive x-axis. A direction of southeast will be +315° or -45°. A direction of southwest will be +225° or -135°.

Then the sum of the displacements in rectangular coordinates is ...
   = (7, -3) + 3*(cos(-45°), sin(-45°)) + 4*(cos(-135°), sin(-135°))
   = (7, -3) + ((√2)/2)*((3, -3) + (-4, -4))
   = (7, -3) + 0.707107*(-1, -7)
   = (6.2929, -7.9497)
Then the Pythagorean theorem is used to find the direct distance from home to this displaced location.
   d = √(6.2929² +(-7.9497)²) ≈ √102.7990
   d ≈ 10.1390 . . . . miles

4 0
3 years ago
compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.
Nina [5.8K]

\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})

We have been given two vectors $\vec{a}$ and $\vec{b}$, we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of$\vec{b}$onto $\vec{a}$means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0
1 year ago
What is the slope of this line?<br> y = -2x + 6
KengaRu [80]

Answer:

<h2>slope = -2</h2>

Step-by-step explanation:

The slope-intercept form of an equation of a line:

<em>y = mx + b</em>

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

<em />

We have the equation:

<em>y = -2x + 6</em>

therefore

<em>m = -2</em>

<em>b = 6</em>

8 0
3 years ago
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