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hammer [34]
3 years ago
8

For the quadratic function f(x)=x^2-6x-27, determine and accurately express each of the key features listed below.

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

1) (x,y) = (0,-27), 2) V(x,y) = (3, -36).

Step-by-step explanation:

1) The ordered pair of the parabola is:

f(0) = 0^{2} - 6\cdot (0) -27

f(0) = -27

(x,y) = (0,-27)

2) The quadratic function needs to be rearranged into the standard form:

y = x^{2}-6\cdot x -27

y = x^{2} - 6\cdot x + 9 -9 -27

y = (x-3)^{2}-36

y + 36 = (x-3)^{2}

The vertex is V(x,y) = (3, -36).

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Answer:

  1. y = -\frac{4}{5} x - \frac{14}{5}
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1. Perpendicular and passes through (4,-6)

m_1 = \frac{5}{4} \\\\m_2 = \frac{-1}{m_1} \\\\m_2 = \frac{-1}{\frac{5}{4} } \\\\m_2 = -\frac{4}{5} \\\\(4,-6)=(x ,y)\\

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y =mx+b\\\\-6 = -\frac{4}{5} (4) + b\\\\-6 = -\frac{16}{5} + b\\\\-6 + \frac{16}{5} = b\\\\-\frac{14}{5} = b\\\\b = -\frac{14}{5}\\\\m = - \frac{4}{5}

Substitute new values into ; y =mx+b.

y = -\frac{4}{5} (x)- (\frac{14}{5} )\\\\y = -\frac{4}{5} x - \frac{14}{5}

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m = \frac{5}{4} \\\\(4,-6)=(x_1,y_1)

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