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Fiesta28 [93]
2 years ago
6

Use elimination to solve 3y-6x=7-4y-3x=9

Mathematics
1 answer:
Masja [62]2 years ago
5 0
Reorder both sides

3y-6x=9
7-4y-3x=9

Multiply both sides
-6x-3y=9
6x+8y=-4

Dived both sides

11y= 5

Y=5/11

Substitute the value of Y

-3x-4(5/11)

Equals —> -14/11

Answer : (5/11 , -14/11)
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Choose any positive integer. Powers of two here are not very interesting, so choose something else. If the number you have chose
Yakvenalex [24]

Answer:

Step-by-step explanation:

Let the integer be 6 for even and 7 for odd (say)

For 6, we divide by 2, now get 3.  Now we multiply by 3 and add 1 to get 10. Now since 10 is even divide by 5, now multiply by 3 and add 1 to get 16.  Now divide by 2 again by 2 again by 2 again by 2 till we get rid of even numbers.

The result is 1, so multiply by 3 and add 1 we get 4 now divide 2 times by 2 to get 1, thus this result now again repeats after 2 times.

Say if we select off number 3, multiply by 3 and add 1 to get 10 now divide by 5, now repeat the same process as above for 5 until we get 1 and it gets repeated every third time.

Thus whether odd or even after some processes, we get 1 and the process again and again returns to 1.

5 0
3 years ago
Which one is greater 3/10 or 2/5
Andreyy89

Answer:

2/5

Step-by-step explanation:

2/5=4/10

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2 years ago
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8 0
3 years ago
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Vinil7 [7]

Answer: A. x\geq21\dfrac{2}{3} .

Step-by-step explanation:

The given inequation: 81-1\dfrac{1}{5}x\leq55

\Rightarrow\ 81-\dfrac{6}{5}x\leq55

Multiplying 5 on both the sides, we get

5(81-\dfrac{6}{5}x)\leq5\times55\\\\\Rightarrow\ 405-6x\leq275\\\\\Rightarrow\ 6x\geq405-275\\\\\Rightarrow\ 6x\geq130\\\\\Rightarrow\ x\geq\dfrac{130}{6}\\\\\Rightarrow\ x\geq\dfrac{65}{3}\\\\\Rightarrow\ x\geq21\dfrac{2}{3}

Hence, the inequality for x is x\geq21\dfrac{2}{3} .

So, the correct option is A. x\geq21\dfrac{2}{3} ..

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3 years ago
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