Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Answer:
3 units right and 1 unit up.
Step-by-step explanation:
Build a rectangle 12 cm high and 5 cm wide (Paint it). Then a) Find the perimeter of the rectangle. B) Find the area of the rectangle. Aiuda porfis.
Length of the rectangle is 12 cm
Breadth of the rectangle is 5 cm
Perimeter is the sum of all sides. For rectangle it is given by :
P = 2(l+b)
⇒ P=2(12+5)
P = 34 cm
Area of a rectangle is equal to the product of its length and breadth.
So,
A = lb
A = 12 cm × 5 cm
⇒A = 60 cm²
Hence, perimeter is 34 cm and area of rectangle is 60 cm².
483,600,000 miles
4 - hundred millions place
8 - ten millions place
3 - millions place
6 - hundred thousands place
0 - ten thousands, thousands, hundreds, tens, and ones place
