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Ira Lisetskai [31]
3 years ago
6

Is 43 odd or even?but the answer don't have to be great i just need a answer

Mathematics
1 answer:
cupoosta [38]3 years ago
4 0
43 is an odd number.
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Pls answe quick and correctly
andriy [413]

Answer:

9890

Step-by-step explanation

7×43×30+5×4×43=9890

4 0
2 years ago
Rafael has 3 times as many blue marbles as he does red marbles . He has a total of 124 marbles. How many read marbles and how ma
34kurt
<span>A quarter of the marbles are red, so there are 124/4 = 31 red marbles. The rest are blue, so there are 124 - 31 = 93 blue marbles.</span>
6 0
3 years ago
After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i
Crazy boy [7]

Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume (V) is calculated by:

V = \frac{4\pi}{3}\cdot R^{3}

Where R is the radius of the tumor.

The percentage decrease in the volume of the tumor (\%V) is expressed by:

\%V = \frac{\Delta V}{V_{o}} \times 100\,\%

Where:

\Delta V - Absolute decrease in the volume of the tumor.

V_{o} - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

\Delta V = V_{o}-V_{f}

\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})

The percentage decrease is finally simplified:

\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%

Given that R_{o} = R and R_{f} = 0.77\cdot R, the percentage decrease in the volume of tumor is:

\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%

\%V = 54.34\,\%

The volume of the tumor experimented a decrease of 54.34 percent.

5 0
3 years ago
Which function is graphed below? Select all that apply.
Lelu [443]
Can you add a photo?
6 0
3 years ago
HELP ME PLEASEEEEEEEEEEEEEE
CaHeK987 [17]
I think x=24 but not sure
7 0
3 years ago
Read 2 more answers
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