4 years ago

The equation of a parabola is (y−3)2=20(x+1) .

2 answers:

6 0

2(y - 3) = 20(x - 1)
(h, k) = (1, 3)
(y - 3) = 10(x - 1)
4p = 10
p = $\frac{5}{2}$
x = h - p
x = 1 - $\frac{5}{2}$
x = - $\frac{3}{2}$
Hope that helped! If it's wrong, I'm sorry; I only learned about directrix today.

MrRa [10]4 years ago

4 0

Answer:

X=-6

Step-by-step explanation:

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katen-ka-za [31]

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3 years ago

Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.

makkiz [27]

Can't be done without knowing what $f$ is...

But I can tell you that the average value of $f$ is given by

$\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}$

At the very least, we can compute the denominator, which is just the area of $R$ . You have

$\displaystyle\iint_R\mathrm dx\,\mathrm dy=\int_{x=0}^{x=1}\int_{y=x}^{y=1}\mathrm dy\,\mathrm dx=\int_0^1(1-x)\,\mathrm dx=\dfrac12$

so the average value will be

$2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy$