3 years ago

If (a+b+c) = 5 and ab+bc+ac = 10. Prove that a3+b3+c3 -3abc = -25

Mathematics

1 answer:

maks197457 [2]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Using the identity

(a + b + c)³ = a³ + b³ + c³ + 3 [ (a + b + c)(ab + bc + ac) - abc ], then

5³ = a³ + b³ + c³ + 3(5 × 10) - 3abc, that is

125 = a³ + b³ + c³ + 150 - 3abc, hence

a³ + b³ + c³ - 3abc = 125 - 150 = - 25

You might be interested in

The baker pays $0.50 per pound for sugar and $0.75 per pound for butter. Write an expression that shows how much the baker will

stiks02 [169]

.5(20)+.75(6)=$14.50

3 0

3 years ago

Read 2 more answers

Helppp! I dont completly get the conceptttt

Sergio [31]

1/7 is a
0.2 is b
3/9 is c

Hope you find this helpful!
Brainliest and a like is much appreciated!

3 0

2 years ago

Compute using significant digits. What is the area of a parallelogram with length 17.25 mm and width 5.065 mm?

Dmitriy789 [7]

Answer: Option 'a' is correct

Step-by-step explanation:

Since we have given that

Length of parallelogram =17.25 mm

Width of parallelogram =5.065 mm

As we know the formula for " Area of parallelogram"

Area of parallelogram is given by

$Area= length \times breadth\\\\17.25\times 5.065=87.03 \ mm^2$

Hence, option 'a' is correct .

8 0

3 years ago

What is 7 1/8 x 2 5/6?

nignag [31]

The answer is 20.1875

6 0

3 years ago

Read 2 more answers

The drawing of a building, shown below, has a scale of 1 in to 30 ft. what is the actual height, in ft, of the building

11111nata11111 [884]

The answer is: 22.4 hope it helps :)

6 0

3 years ago

If (a+b+c) = 5 and ab+bc+ac = 10. Prove that a3+b3+c3 -3abc = -25​

If (a+b+c) = 5 and ab+bc+ac = 10. Prove that a3+b3+c3 -3abc = -25