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Dafna11 [192]
3 years ago
11

If (a+b+c) = 5 and ab+bc+ac = 10. Prove that a3+b3+c3 -3abc = -25​

Mathematics
1 answer:
maks197457 [2]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

Using the identity

(a + b + c)³ = a³ + b³ + c³ + 3 [ (a + b + c)(ab + bc + ac) - abc ], then

5³ = a³ + b³ + c³ + 3(5 × 10) - 3abc, that is

125 = a³ + b³ + c³ + 150 - 3abc, hence

a³ + b³ + c³ - 3abc = 125 - 150 = - 25

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a multiplication that corresponds to each division 10 divided by 5=?, b. 4.5 divided by 3, 1/2 dvided by 4=?
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Answer:

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