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vazorg [7]
3 years ago
9

The baker pays $0.50 per pound for sugar and $0.75 per pound for butter. Write an expression that shows how much the baker will

spend if he buys 6 pounds of butter and 20 pounds of sugar.
Mathematics
2 answers:
yarga [219]3 years ago
6 0

(.5x20)+(.75x6)=$14.50

stiks02 [169]3 years ago
3 0
.5(20)+.75(6)=$14.50
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There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,
lys-0071 [83]

<h2 /><h2>Here we go ~ </h2>

According to given information there are :

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  • 6 yellow balls

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<h3>1. what is the probability that the ball chosen is red ?</h3>

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\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{total \: red \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{5}{25}

\qquad \sf  \dashrightarrow \: p(red) =  \dfrac{1}{5}

<h3>2. what is the probability that the ball chosen is blue ?</h3>

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{total \: blue \: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(blue) =  \dfrac{4}{25}

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{total \: yellow\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(yellow) =  \dfrac{6}{25}

<h3>4. what is the probability that the ball chosen is green ?</h3>

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{total \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{10}{25}

\qquad \sf  \dashrightarrow \: p(green) =  \dfrac{2}{5}

<h3>5. what is the probability that the ball chosen is not green ?</h3>

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{total \: non \: green\: balls}{total \: balls}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{15}{25}

\qquad \sf  \dashrightarrow \: p(not \: green) =  \dfrac{3}{5}

3 0
2 years ago
Can someone help me with this math homework please!
Daniel [21]

Answer:

1st, 2nd and 6th options

Step-by-step explanation:

Given

\frac{2}{3} - x + \frac{1}{6} = 6x ( multiply through by 6 to clear the fractions )

4 - 6x + 1 = 36x ← option 1 will have the same solution set

----------------------------------------------------------------------

Adding the 2 fractions on the left side gives

\frac{4}{6} +\frac{1}{6} - x = 6x , that is

\frac{5}{6} - x = 6x ← option 2 will have the same solution set

------------------------------------------------------------------------

From

4 - 6x + 1 = 36x ( add 6x to both sides )

5 = 42x ← option 6 will have the same solution set

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2 years ago
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