The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
<h3>How to determine the inverse relation?</h3>
The function is given as
f(x)=1/3x^2-3x+5
Start by rewriting the function in vertex form
f(x) = 1/3(x - 9/2)^2 -7/4
Rewrite the function as
y = 1/3(x - 9/2)^2 -7/4
Swap x and y
x = 1/3(y - 9/2)^2 -7/4
Add 7/4 to both sides
x + 7/4= 1/3(y - 9/2)^2
Multiply by 3
3x + 21/4= (y - 9/2)^2
Take the square roots
y - 9/2 = √(3x + 21/4)
This gives
y = 9/2 + √(3x + 21/4)
Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)
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C'=1.5
c/c'=d/d'
c/1.5=8
c=12
hope that helps :)
Answer:
Take rabbit across
go back
Take fox across and go back across with rabbit
take carrots across and leave them with fox
go back and get rabbit
Step-by-step explanation:
Common ratio means that you will be multiplying from the first number to get the second number.
To find the ratio we will work backwards, from right to left, and divide instead of multiply.
-43/-21.5 = 1/2
-86/-43= 1/2
-182/-86 = 1/2
r = 1/2
