Answer:
The probabability is ![\frac{85}{100} =0.850](https://tex.z-dn.net/?f=%5Cfrac%7B85%7D%7B100%7D%20%3D0.850)
Step-by-step explanation:
We are going to suppose that each score has the same probability.
For example :
![P(66) = P(89)](https://tex.z-dn.net/?f=P%2866%29%20%3D%20P%2889%29)
Where P(66) is the probability of score a 66 and P(89) is the probability of score an 89
If A is a certain score :
![P(A) = \frac{CasesWhereAOccurs}{Total Cases}](https://tex.z-dn.net/?f=P%28A%29%20%3D%20%5Cfrac%7BCasesWhereAOccurs%7D%7BTotal%20Cases%7D)
In the exercise :
![P(1) = P(2)=...=P(100)=\frac{1}{100} =0.01](https://tex.z-dn.net/?f=P%281%29%20%3D%20P%282%29%3D...%3DP%28100%29%3D%5Cfrac%7B1%7D%7B100%7D%20%3D0.01)
Bart must score higher than an 85 on the final exam.
We are looking for the probability of the event : ''Bart obtains a 1 or a 2 or ... or a 85''
This can be written in terms of events as :
P(1∪2∪...∪85) = P(1) + P(2) + ... + P(85)
As we consider each event as independent
![P(1) + P(2) + ... + P(85) =\frac{1}{100} +\frac{1}{100} +...+\frac{1}{100} =(85).\frac{1}{100} \\P(Not Score Higher Than An 85)=\frac{85}{100}](https://tex.z-dn.net/?f=P%281%29%20%2B%20P%282%29%20%2B%20...%20%2B%20P%2885%29%20%3D%5Cfrac%7B1%7D%7B100%7D%20%2B%5Cfrac%7B1%7D%7B100%7D%20%2B...%2B%5Cfrac%7B1%7D%7B100%7D%20%3D%2885%29.%5Cfrac%7B1%7D%7B100%7D%20%5C%5CP%28Not%20Score%20Higher%20Than%20An%2085%29%3D%5Cfrac%7B85%7D%7B100%7D)
Answer:
-14(2x+1)
Step-by-step explanation:
Factor out the GCF, which is 14.
Answer:
|5| = |-5|
|-4| > -6
-5 < |-9|
|-4| < 7
Step-by-step explanation:
In absolute value the negative signs don't matter and you have to think of them as just the number.
EXAMPLE
|-4| = 4
|5| = 5
NON EXAMPLE
|-4| = -4
If three consecutive values add to 567 the middle value must be 567/3 = 189
Since the values are multiples of 9, the other values must be 189 - 9 and 189 + 9
The three values are 180, 189, 198
Answer:
Step-by-step explanation:
Domain : Set of all possible input values (x-values) on a graph
Codomain : Set of all possible out values for the input values (y-values) on the graph
Range : Actual output values for the input values (x-values) given on the graph.
Therefore, for the given graph,
Domain : (-∞, ∞)
Codomain : (-∞, 2]
Range : (-∞, 2]
From the given graph every input value there is a image or output value.
Therefore, the given function is onto.