Answer:
The probability that the wait time is greater than 14 minutes is 0.4786.
Step-by-step explanation:
The random variable <em>X</em> is defined as the waiting time to be seated at a restaurant during the evening.
The average waiting time is, <em>β</em> = 19 minutes.
The random variable <em>X</em> follows an Exponential distribution with parameter .
The probability distribution function of <em>X</em> is:
Compute the value of the event (<em>X</em> > 14) as follows:
Thus, the probability that the wait time is greater than 14 minutes is 0.4786.
Answer:
the population means are known the population variances are assumed equal but unknown
Step-by-step explanation:
If σ1= σ2 (= σ) but unknown , then the biased pooled or combined estimate of the common variance σ² ( the term common variance means that each population has the same variance ) is given by
Sp²= (n1-1) s1² + (n2-1) s2²/ n1+ n2- 2
So first assumption is correct.
When the population variances are assumed unequal and unknown
If σ1 ≠ σ2 but unknown
we use the sample estimates s1 and s2 to compute the standard error of the difference between the means.
S(x1`- x2`) = √s1²/ n1 + s2²/n2
So this is does not apply here.
Answer:
In the explanation section.
Step-by-step explanation:
1. Table of values for the equation y = 2.3^x
- (-2, 0.189)
- (-1, 0.434)
- (0, 1)
- (1, 2.3)
- (2, 5.29)
- Graph with the green line
2. Table of values for the equations y = 4(1/2)^x
- (-2, 16)
- (-1, 8)
- (0, 4)
- (1, 2)
- (2, 1)
- Graph with blue line
Answer:
15x square units
Step-by-step explanation:
3x x 5 =
15x square units
Hope that helps!
The lcm of 8, 28, and 24 is 168