B and C
3^3 = 27
the cubed root of 27 is 3
ED = 68
Angle GKH = 31
ABD = 224
Angle AKB = 112
2t+3n=9 2(2)+3n=9
+5t-3n=5 (the 3n cancel out) 4+3n=9
7t=14 3n=5
t=2 n=5/3 or 1.67
Answer: The shape of the cross section will be triangular.
Step-by-step explanation:
The cross section is the shape the shows when you cut a straight line. no matter where you cut it, you will still get a triangle.
-- Subtract K from each side of the equation.
8/5 = 0
-- There is no value for K that can make this a true statement. So the original equation has no solution.
