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Nimfa-mama [501]
3 years ago
13

David wants to hang a mirror in his room. The mirror and frame must have an area of 8 square feet. The mirror is 2 feet wide and

3 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?
Mathematics
1 answer:
hoa [83]3 years ago
8 0

Answer:

4x^2+10x-2=0

Step-by-step explanation:

So the total area of mirror: 2*3 = 6 ft sq

8-6 = 2 ft sq is the area of the frame

x is the thickness of the frame

so we have (2*x)*2+(3*x)*2+x*x*4= 2

4x+6x+4x^2=2

-> 4x^2+10x-2=0

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We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1 

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substitute the limits:

5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0

solve for b

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Match the number set or type of number with the correct category
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An integer is a rational number; 1/2 is a rational ratio with a denominator of 1; 0.4545 is a rational decimal; 0.44 is a irrational decimal and 0 is a rational whole numbers.

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The category irrational number can be applied to numbers that cannot be expresses as ratios or fractions. This includes decimals that do not terminate and are not repeating such as 0.44454...

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6 0
2 years ago
Given one zero of the polynomial function, find the other zeros.
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

You need to use synthetic division to do all of these.  The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.

a.  3I   1   3   -34   48

I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.

First step is to bring down the first number after the bold line, 1.

3I   1    3    -34    48

   _____________

      1

then multiply it by the 3 and put it up under the 3.  Add those together:

3I    1    3    -34    48

           3

----------------------------

      1     6

Now I'm going to multiply the 6 by the 3 after the bold line and add:

3I    1     3     -34     48                                                                                                    

             3      18

_________________

      1      6     -16

Same process, I'm going to multiply the -16 by the 3 after the bold line and add:

3I      1      3      -34      48

                3       18     -48

___________________

        1       6      -16       0

That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

x^2+6x-16=0

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I am assuming that since you are doing synthetic division that you have already learned the quadratic formula.  You could use that or just "regular" factoring would do the trick on all of them.

Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.

You got this!        

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