X + y + z = 2
x - y + 5z = 6
cancelando +y com -y:
x + z = 2*(-5)
x + 5z = 6
-5x -5z = -10
...x +5z = 6
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-4x = -4 *(-1)
4x = 4
x = 4/4
x = 1
x + z = 2
1 + z = 2
z = 2 - 1
z = 1
x + y + z = 2
1 + y + 1 = 2
2 + y = 2
y = 2 - 2
y = 0
S: {x, y, z} = {1, 0, 1}
5x-1= 26
5x-1+1= 26+1
5x= 27
Divide by 5 for 5x and 27
5x/5= 27/5
x= 27/5
Answer is x= 27/5 - A)
What you want to do is change the variable positions of X and Y
So it would be a new equation of
x = 1/2y + 3
Then you would need Y to be by itself so you solve for that
x-3 = 1/2 y
then,
2(x-3) = y
Your inverse function is 2(x-3) = y
Hope this helped :D
The answer to the question
Standard form:6x^3+x^2-6x+1
The degree is 3
