Question

PLEASE HELP ME WITH THIS QUESTION ITS URGENT!!!

Answer 1

Start by distributing the exponent to each of the terms in $(2u)^{3}$.  This will become $2^{3} u^{3}$, and $2^{3} =8$.  Now, the expression is:

$\frac{2u^{3} v^{2} }{8u^{3} * u^{2} }$.

We can now simplify the bottom to read: $8u^{5}$ because when multiplying variables raised to an exponent, we add the exponents.  The expression now looks like:

$\frac{2u^{3} v^{2} }{8u^{5} }$

The 2/8 simplifies to 1/4:

$\frac{u^{3} v^{2} }{4u^{5} }$

Now, we have two u terms on the top and bottom.  When dividing variables raised to an exponent, we subtract the exponents.  However, since 3-5=-2, the term will be on the bottom to avoid the negative exponent.  The final answer is:

$\frac{v^{2} }{4u^{2} }$

Hope this makes sense!!