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3 years ago

12 1 point The mZCAD __degrees D 158 A D type your answer...

Mathematics

1 answer:

9966 [12]3 years ago

6 0

bahala ka mag aral ka nga

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Rob has 7 ones. nick has 5 ones. they put all their ones together. what number did they

levacccp [35]

It would be 12 ones it would be this because you have to add 7+ 5

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3 years ago

Solve using substitution technique; -3x+y=2, 12x-4y=-8

vladimir1956 [14]

The first equation is easier to solve for y than is the 2nd: y = 3x+2. Subst. 3x+2 for y in the second equation:

12x - 4(3x+2) = -8

Expanding, 12x =12x -8 = -8

This is always true, no matter the value of x. Thus, the solution set is "all real numbers."

4 0

4 years ago

1/sin10°-√3/cos10°=4

Alexandra [31]

Answer:

$\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=4$

Step-by-step explanation:

Given the expression

$\frac{1}{\sin \left(10^{\circ \:}\right)}-\frac{\sqrt{3}}{\cos \left(10^{\circ \:}\right)}=4$

Taking the left-hand side and solving it

$\frac{1}{\sin \left(10^{\circ \:}\right)}-\frac{\sqrt{3}}{\cos \left(10^{\circ \:}\right)}$

$\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=5.76$

and

$\frac{\sqrt{3}}{\cos \left(10^{\circ \:\:}\right)}=1.76$

so the expression becomes

$\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=5.76-1.76$

$=4$

Thus, we conclude that

$\frac{1}{\sin \left(10^{\circ \:\:}\right)}\:\:\frac{1}{\sin \:\left(10^{\circ \:\:}\right)}=4$

8 0

3 years ago

Plz help me with this I beg you

zimovet [89]

The answer I’m pretty sure will be -4. (-4+12-36)/7 = -28/7.

4 0

3 years ago

Read 2 more answers

Select the function table that matches the equation below.

Cloud [144]

Answer:

Step-by-step explanation:

-8*-5 + 4 = 28

-8*0+4=4

-8*2+4=-12

3 0

3 years ago

Read 2 more answers