Simplify: –3(y 2)2 – 5 6y
1 answer:
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Answer:
Linked an image
Step-by-step explanation:
Okay, basically since it is y=2co3x you know that the amplitude is 2, so rather than going to +1 and -1, you now go to +2 and -2. Since it's cosine, you also know that you start at the maximum rather than the intercept, so the starting point is at (0,2).
I'm assuming that you need to graph 2 periods, and to find the periods you divide 2pi/b, so, in this case, 2pi/3
Then lastly you need to find the four points between 0 and 2pi/3, so you divide 2pi/3/4 to get 2pi/12=pi/6
If you have any other questions just comment and I'll respond when I see it.
Answer:
a) 0.125
b) 7
c) 0.875 hr
d) 1 hr
e) 0.875
Step-by-step explanation:l
Given:
Arrival rate, λ = 7
Service rate, μ = 8
a) probability that no requests for assistance are in the system (system is idle).
Let's first find p.
a) ρ = λ/μ
Probability that the system is idle =
1 - p
= 1 - 0.875
=0.125
probability that no requests for assistance are in the system is 0.125
b) average number of requests that will be waiting for service will be given as:
λ/(μ - λ)
= 7
(c) Average time in minutes before service
= λ/[μ(μ - λ)]
= 0.875 hour
(d) average time at the reference desk in minutes.
Average time in the system js given as: 1/(μ - λ)
= 1 hour
(e) Probability that a new arrival has to wait for service will be:
λ/μ =
= 0.875
Answer: The mean and variance of Y is $0.25 and $6.19 respectively.
Step-by-step explanation:
Given : You and a friend play a game where you each toss a balanced coin.
sample space for tossing two coins : {TT, HT, TH, HH}
Let Y denotes the winnings on a single play of the game.
You win $1; if the faces are both heads
then P(Y=1)=P(TT)=
You win $6; if the faces are both heads
then P(Y=6)=P(HH)=
You loose $3; if the faces do not match.
then P(Y=1)=P(TH, HT)=
The expected value to win : E(Y)=
Hence, the mean of Y : E(Y)= $0.25
Variance =
Hence, variance of Y = $ 6.19