Find the perimeter of the triangle with coordinates A(5,2), B(5,4), and C(1,1). Round to the nearest tenth.

Mathematics

1 answer:

faltersainse [42]3 years ago

4 0

Answer:

11.1 units

Step-by-step explanation:

We solve for this using the formula when using coordinates (x1 , y1) and (x2, y2)

= √(x2 - x1)² + (y2 - y1)²

A(5,2), B(5,4), and C(1,1).

For AB = √(x2 - x1)² + (y2 - y1)²

= A(5,2), B(5,4)

= √(5 - 5)² +(4 - 2)²

= √ 0² + 2²

= √4

= 2 units

For BC = √(x2 - x1)² + (y2 - y1)²

= B(5,4), C(1,1)

= √(1 - 5)² +(1 - 4)²

= √ -4² + -3²

= √16 + 9

= √25

= 5 units

For AC = √(x2 - x1)² + (y2 - y1)²

A(5,2), C(1,1)

= √(1 - 5)² + (1 - 2)²

= √-4² + -1²

= √16 + 1

= √17

= 4.1231056256 units

The Formula for the Perimeter of Triangle = Side AB + Side BC + Side AC

= 2 units + 5 units + 4.1231056256 units

= 11.1231056256 units.

Approximately the Perimeter of a Triangle to the nearest tenth = 11.1units

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