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3 years ago

CAN SOMEONE PLEASE HELP WITH THIS IT I URGENT

Mathematics

1 answer:

olga_2 [115]3 years ago

4 0

Answer:

Step-by-step explanation:

9+7+2=18

But since there are only 12 people in the class, its overlapping. So 18-2(the people that have nether), is 16.

So 16-12 is 4. Therefore 4 people have both a brother and a sister.

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3y-3.5/3y+6=17/25.5. find the value of y. give the scale factor of the polygon

Mekhanik [1.2K]

Hi the answer to your question is

((3y - 3.5) / (3y + 6)) * 25.5 = (17 / 25.5) * 25.5

((3y - 3.5) / (3y + 6)) * 25.5 = 17 (76.5y - 89.25) / (3y + 6) = 17

((76.5y - 89.25) / (3y + 6)) * (3y + 6) = 17 * (3y + 6) 76.5y - 89.25 = 51y + 102 76.5y - 51y = 102 + 89.25

25.5y = 191.25

y = 191.25 / 25.5

y = 7.5

3 0

3 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

Ugo [173]

Answer:

$Side\ B = 6.0$

$\alpha = 56.3$

$\theta = 93.7$

Step-by-step explanation:

Given

Let the three sides be represented with A, B, C

Let the angles be represented with $\alpha, \beta, \theta$

[See Attachment for Triangle]

$A = 10cm$

$C = 12cm$

$\beta = 30$

What the question is to calculate the third length (Side B) and the other 2 angles ( $\alpha\ and\ \theta$ )

Solving for Side B;

When two angles of a triangle are known, the third side is calculated as thus;

$B^2 = A^2 + C^2 - 2ABCos\beta$

Substitute: $A = 10$ , $C =12$ ; $\beta = 30$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30$

$B^2 = 100 + 144 - 240*0.86602540378$

$B^2 = 100 + 144 - 207.846096907$

$B^2 = 36.153903093$

Take Square root of both sides

$\sqrt{B^2} = \sqrt{36.153903093}$

$B = \sqrt{36.153903093}$

$B = 6.0128115797$

$B = 6.0$ (Approximated)

Calculating Angle $\alpha$

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute: $A = 10$ , $C =12$ ; $B = 6$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha$

$100 = 36 + 144 - 144 *Cos\alpha$

$100 = 180 - 144 *Cos\alpha$

Subtract 180 from both sides

$100 - 180 = 180 - 180 - 144 *Cos\alpha$

$-80 = - 144 *Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}$

$\frac{-80}{-144} = Cos\alpha$

$0.5555556 = Cos\alpha$

Take arccos of both sides

$Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)$

$Cos^{-1}(0.5555556) = \alpha$

$56.25098078 = \alpha$

$\alpha = 56.3$ (Approximated)

Calculating $\theta$

Sum of angles in a triangle = 180

Hence;

$\alpha + \beta + \theta = 180$

$30 + 56.3 + \theta = 180$

$86.3 + \theta = 180$

Make $\theta$ the subject of formula

$\theta = 180 - 86.3$

$\theta = 93.7$

5 0

3 years ago

Please help me i will give brianliest

allsm [11]

Answer:

8 is the right answer

Step-by-step explanation:

in triangle swu,, wT bisect and perpendicular on su

so the triangle is isosceles triangle

therfore,Sw =, 8

4 0

3 years ago

Which quantity is proportional to 90⁄2

scoundrel [369]

Answer:

45/1 and 180/41. True

2. False

3. False

Step-by-step explanation:

4 0

3 years ago

A rectangular garden has a walkway around it. The area of the garden is 6(6.5x + 2.5). The combined area of the garden and the w

Rasek [7]

According to the information given in the exercise, the following expression represents the area of the rectangular garden:

$6\mleft(6.5x+2.5\mright)$

And the following expression represents the combined area of the walkway around the rectangular garden and the area of the garden:

$6.5\mleft(8x+6\mright)$

You can identify that the word "combined" indicates that that expression was obtained by adding both areas.

Knowing the above, you can set up the following equation:

$6(6.5x+2.5)+A=6.5(8x+6)$

Where "A" is the area of the walkway around the rectangular garden.

Solving for "A", you get the following expression:

$\begin{gathered} A=6.5(8x+6)-6(6.5x+2.5) \\ A=52x+39-39x-15 \\ A=13x+24 \end{gathered}$

The answer is:

$13x+24$

7 0

1 year ago