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finlep [7]
3 years ago
10

Find the slope from the table below. ​

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
6 0
Slope for the function is -1/3.5.
Ilia_Sergeevich [38]3 years ago
5 0
-1/3.5 and in decimal form is -0.28571428571
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wlad13 [49]
64/8 = 8
5x8 = 40

If 1:4 = 1/4 then do 40/4 = 10
If 1:4 = 14 then do 40-14 = 26

The answer might be either 10 or 26 guitarist that play classical solos depending on what 1:4 means.

I hope this helps! :D
3 0
3 years ago
A CD usually sells for $13.00. If the CD is 30% off, and sales tax is 5%, what is the total price of the CD, including tax?
amid [387]
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3 0
3 years ago
Select the correct answer. Which number has a repeating decimal form? A. 15 B. 11/25 C. 3/20 D. 2/6​
ivanzaharov [21]

Answer:

Step-by-step explanation: im pretty sure that its b so there you go

4 0
3 years ago
Read 2 more answers
Which set of measures would give a clear conclusion about the data. Help please.
adell [148]
<h2>We need more details for this question. We may not understand it because we could not see the data.</h2>

8 0
3 years ago
X^2 + 4x - 9 = (x + a)^2 + b<br><br> Find the value of a and the value of b
REY [17]

Answer:

<h2>a = 2, b = -13</h2>

Step-by-step explanation:

We have three ways.

(a+b)^2=a^2+2ab+b^2\qquad(*)

\bold{1.}\\\\x^2+4x-9=x^2+2(x)(2)-9=\underbrace{x^2+2(x)(2)+2^2}_{(*)}-2^2-9\\\\=(x+2)^2-4-9=(x+2)^2-13\\\\x^2+4x-9=(x+a)^2+b\\\Downarrow\\(x+2)^2-13=(x+a)^2+b\Rightarrow \boxed{\bold{a=2, b=-13}}

\bold{2.}\\\\\underbrace{(x+a)^2}_{(*)}+b=x^2+2ax+a^2+b\\\\x^2+4x-9=x^2+2ax+(a^2+b)\Rightarrow 4=2a\ \text{and}\ -9=a^2+b\\\\4=2a\qquad\text{divide both sides by 2}\\\\\dfrac{4}{2}=\dfrac{2a}{2}\\\\2=a\to \boxed{\bold{a=2}}\\\\\text{Substitute to the second equation:}\\\\-9=2^2+b\\\\-9=4+b\qquad\text{subtract 4 from both sides}\\\\-9-4=4-4+b\\\\-13=b\to \boxed{\bold{b=-13}}

\bold{3.}\\\\(x+a)^2+b-\text{it's a vertex form of an equation of a parabola}\\\\\text{Let}\ y=a(x-h)^2+k\ -\ \text{the euation of a parabola}\ y=ax^2+bx+c.\\\\\text{Then}\ h=\dfrac{-b}{2a},\ k=\dfrac{-(b^2-4ac)}{4a}\\\\x^2+4x-9\to a=1,\ b=4,\ c=-9\\\\h=\dfrac{-4}{2(1)}=\dfrac{-4}{2}=-2\\\\k=\dfrac{-(4^2-4(1)(-9))}{4(1)}=\dfrac{-(16+36)}{4}=\dfrac{-42}{4}=-13\\\\\text{Therefore}\\\\x^2+4x-9=(x+a)^2+b\\\\(x-(-2))^2+(-13)=(x+a)^2+b\\\\(x+2)^2-13=(x+a)^2+b\to\boxed{\bold{a=2,\ b=-13}}

4 0
3 years ago
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