SOLUTION
The mean is 4min
standard deviation is 1min
the z score is

where

then we have

The probability the call lasted less than 3 min will be
Therefore, the probability that (z < -1 ) is
[tex]\begin{gathered} Pr(z<-1)=Pr(0
Hence, the percentage of the calls that lasted less than 3 min is 16%
Answer:
-17y + 16x
Step-by-step explanation:
-3(3y - 2x) + 2(5x - 4y) = -9y + 6x + 10x - 8y = -17Y + 16X.
If it is helpful, plz give me Brainliest.
There we have an information of two functions 
Using this two functions
, we need to find the composition of functions (h\circ g)(t).
The composition of two functions h and g is the new function , by performing g first and then performing h.



Composition of h and g (t) = 

First plugin the value of 


We know that
, we need to find h(3t+3),
That is, to replace t by 3t+3,

Now distribute 2 into 3t+3,

Now plug in 


Thus the solution is (D).