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DerKrebs [107]
3 years ago
11

Denzel wants to work out the density of a block of wood the block of wood is in the shape of the cuboid

Mathematics
1 answer:
marishachu [46]3 years ago
5 0

Answer:

Density = 1.094g/cm^3

Step-by-step explanation:

Given

Length = 17.7cm

Width = 8.3cm

Height = 13.0cm

Mass = 2090g

See attachment

Required

Determine the density of the wood

First, we calculate the volume of the wood.

Volume = Length * Width * Height

Substitute values for Length, Width and Height

Volume = 17.7cm * 8.3cm * 13.0cm

Volume = 1909.83cm^3

The density is:

Density = \frac{Mass}{Volume}

Density = \frac{2090g}{1909.83cm^3}

Density = 1.094g/cm^3<em> --- approximated</em>

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vazorg [7]

Answer:

Line 1 to lin2 2= I think D or maybe A.. Mainly D

line 2 to line 3= A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The are of a shaded region is 118 ft squared. Which equation can be- used to find the value of X, in feet?
Triss [41]

Answer:

x^2+ 18x -130=0

Step-by-step explanation:

Given

See attachment for diagram

Required

The equation to find x

First, calculate the area of the big rectangle using:

Area = Length * Width

So:

A_1 = (x + 6) * (3x - 2)

The smaller rectangle

A_2 = (x - 1) * (2x)

The difference between this areas give the area of the shaded region.

So:

A_1 - A_1 = 118

(x+6)*(3x-2) - (x-1)*2x = 118

Open brackets

3x^2 - 2x + 18x -12 -2x^2 +2x = 118

Collect like terms

3x^2 -2x^2- 2x +2x+ 18x -12   - 118=0

x^2+ 18x -130=0

<em>The above equation can be used to solve for x</em>

4 0
3 years ago
A rectangle has a perimeter of 34 cm and an area of 52 cm2. its length is 5 more than twice its width. write and solve a system
Vsevolod [243]
Width=4cm
length=13cm

3 0
3 years ago
You operate a gaming website, www.mudbeast.net, where users must pay a small fee to log on. When you charged $4 the demand was 5
sertanlavr [38]
A) Demand function

price (x)          demand (D(x))

4                      540

3.50                  810

D - 540          810 - 540
----------- =  -----------------
x - 4               3.50 - 4

D - 540
----------- = - 540
x - 4

D - 540 = - 540(x - 4)

D = -540x + 2160 + 540

D = 2700 - 540x

D(x) = 2700 - 540x

Revenue function, R(x)

R(x) = price * demand = x * D(x)

R(x) = x* (2700 - 540x) = 2700x - 540x^2

b) Profit, P(x)

profit = revenue - cost

P(x) = R(x) - 30

P(x) = [2700x - 540x^2] - 30

P(x) = 2700x - 540x^2 - 30

Largest possible profit => vertex of the parabola

vertex of 2700x - 540x^2 - 30

When you calculate the vertex you find x = 5 /2

=> P(x) = 3345

Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.




5 0
3 years ago
Can a -150/10 be classified as both a rational number and a integer
irakobra [83]
Yes! This is because -150/10 can be simplified to be -15, which is a rational number.

The word “rational” sounds like another math word you’ve heard of before. Do you know what it is?

Well, it’s “ratio”!! Ratios can be seen in the forms x:y and x/y.


ANY RATIONAL NUMBER HAS THE ABILITY TO BE WRITTEN AS A RATIO!! This will completely exclude numbers with super long decimal points (ex: 1.2345678809928374737272828...)

This number also meets the requirements of being an integer. An integer is any whole number (this excludes decimals and fractions)

I know it’s written as a fraction. However, the fraction could be simplified, making it -15, which means this is both a rational number and an integer!!
6 0
3 years ago
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