Third term = t3 = ar^2 = 444 eq. (1)
Seventh term = t7 = ar^6 = 7104 eq. (2)
By solving (1) and (2) we get,
ar^2 = 444
=> a = 444 / r^2 eq. (3)
And ar^6 = 7104
(444/r^2)r^6 = 7104
444 r^4 = 7104
r^4 = 7104/444
= 16
r2 = 4
r = 2
Substitute r value in (3)
a = 444 / r^2
= 444 / 2^2
= 444 / 4
= 111
Therefore a = 111 and r = 2
Therefore t6 = ar^5
= 111(2)^5
= 111(32)
= 3552.
<span>Therefore the 6th term in the geometric series is 3552.</span>
Answer:
x = 3
Step-by-step explanation:
First distribute
2x + 4x - 4 = 2 + 4x
combine like terms
6x - 4 = 2 + 4x
continue
2x - 4 = 2
add 4 to both sides
2x = 6
divide both sides by 2
x = 3
Answer:
Option B.
Step-by-step explanation:
Given information:
Σ(x − M) = 44
where, M is mean.
Sample size = 12
The computational formula for sample variance is
where, M is sample mean and N is sample size.
Substitute Σ(x − M) = 44 and N=12 in the above formula.
The sample variance is 4.0.
Therefore, the correct option is B.
Try this option:
the rule: if f(-x)=f(x), then the function f(x) is even, if f(-x)=-f(x) then the function is odd.
1. f(x)=-5x⁴-2;
if to substitute x→(-x), then f(-x)=-5*(-x)⁴-2; ⇔ f(-x)=-5x⁴-2, in other words f(x)=f(-x), it means that this function is even.
2. f(x)=x³+2x.
if to substitute x→(-x), then f(-x)=(-x)³+2*(-x); ⇔ f(-x)=-(x³+2x), in other words f(-x)=-f(x), it means that this function is odd.
Answer:
one half of two fifths of x would be equivalent to one fifth of x
