-3x+7y=5 (x2) -> -6x+14y=10

-6x+14y=10
-8x+14y=-10
——————— -
2x=20
x=20/20
x=1

Susbstitute x=1,

-8x+14y=-10
-8(1)+14y=-10
-8+14y=-10
14y=-10+8
14y=-2
y=-2/14
y=-1/7

I hope it helps

5 0

2 years ago

Kardal did a study to determine the correlation between men’s heights, x, and their shoe sizes, y, and found the following data:

joja [24]

Answer:

First and Second option

Step-by-step explanation:

The prediction is reasonable

No data is given in the scatterplot for a height of 80 inches, but a shoe size can still be predicted

Are the correct answers

8 0

2 years ago

Read 2 more answers

Tai ran from his house to a position 300 m south of his home in 100 seconds what was his velocity

ladessa [460]

Velocity = distance / time
= 300m / 100s
= 3 m/s

8 0

2 years ago

Find the vertices and foci of the hyperbola with equation quantity x minus 5 squared divided by 144 minus the quantity of y minu

Serjik [45]

$\bf \textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases}\\\\ -------------------------------$

$\bf \cfrac{(x-5)^2}{144}-\cfrac{(y-4)^2}{81}=1\implies \cfrac{(x-5)^2}{12^2}-\cfrac{(y-4)^2}{9^2}=1 \\\\\\ \begin{cases} h=5\\ k=4\\ a=12\\ b=9 \end{cases}\implies c=\sqrt{144+81}\implies c=\sqrt{225}\implies c=15 \\\\\\ \stackrel{center}{(5,4)}\qquad \qquad \stackrel{\textit{because is a horizontal traverse hyperbola}}{\stackrel{foci}{\stackrel{(5\pm 15,4)}{(20,4),(-10,4)}}\qquad \qquad \stackrel{vertices}{\stackrel{(5\pm 12,4)}{(17,4),(-7,4)}}}$

5 0

3 years ago