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Eddi Din [679]
3 years ago
13

What type of association would you expect to see between the amount of fog in the sky and the distance that a pilot can see? A)

Positive association B) Negative association C) No association D) There is not enough information to tell
Mathematics
1 answer:
Blizzard [7]3 years ago
7 0
We can make a conclusion that the more fog there is, the less distance the pilot can see. this means that there is a negative association because if this were graphed, the slop would be negative, as the x-axis (amount of fog) increases and the y-axis (distance pilot can see) decreases.
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What is a shape that has <br> 3 faces<br> 2 edges<br> No vertices ??<br> Please help!
mart [117]
Hello!

A cylinder has 3 faces 2 edges and 0 vertices

The answer is cylinder

Hope this helps!
6 0
3 years ago
Assume that 12 people, including the husband and wife pair, apply for 4 sales positions. People are hired at random.
konstantin123 [22]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.

-----------------------------------------------------------------------------------------------


Selecting 4 people out of 12 can be done in :

\displaystyle{C(12, 4)= \frac{12!}{4!8!}= \frac{12\cdot11\cdot10\cdot9\cdot8!}{4!8!}= \frac{12\cdot11\cdot10\cdot9}{4!}=11\cdot5\cdot9= 495       many ways.


All the possible groups of 4 people, where the husband and wife are included, can be done in C(10, 2) many ways, since we only calculate the possible choices of 2 out of 10 people, to complete the groups of 4.


\displaystyle{ C(10, 2)= \frac{10!}{2!8!}= \frac{10\cdot9}{2}=45


Thus, the 

<span>probability that both the husband and wife are hired is 45/495=0.09


Part 2)

The probability that one is hired and the other is not = 

P(husband hired, wife not hired) + P(wife hired, husband not hired)

these 2 are clearly equal, so it is enough to calculate one.


Consider the case : husband hired, wife not hired.

assuming the husband is hired, we have to calculate the possible groups of 3 that can be formed from 11-1 (the wife)=10 people.

this is 
</span>

\displaystyle{ C(10, 3)= \frac{10!}{3!7!}= \frac{10 \cdot9 \cdot8}{3\cdot2}=10\cdot3\cdot4=120


thus, 


P(husband hired, wife not hired)=120/495=0.24


thus, 

The probability that one is hired and the other is not = 

P(husband hired, wife not hired) + P(wife hired, husband not hired) =

0.24+0.24=0.48



Answer:


A) 0.09


B) 0.48

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3 years ago
What is the measure of side V’W’?
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Hello I have to right 24 characters but I need some more questions lol but 24
6 0
3 years ago
Find the slope of the line.
lukranit [14]

Answer:

0

Step-by-step explanation:

slope = dy/dx

= 0/x

= 0

7 0
3 years ago
What is 38.5 as a fraction in simplest form?
aivan3 [116]
38.5 is equal to 38 1/2 
38*2+1= 77, so the fraction in its simplest form is 77/2
6 0
4 years ago
Read 2 more answers
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