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Eddi Din [679]
3 years ago
13

What type of association would you expect to see between the amount of fog in the sky and the distance that a pilot can see? A)

Positive association B) Negative association C) No association D) There is not enough information to tell
Mathematics
1 answer:
Blizzard [7]3 years ago
7 0
We can make a conclusion that the more fog there is, the less distance the pilot can see. this means that there is a negative association because if this were graphed, the slop would be negative, as the x-axis (amount of fog) increases and the y-axis (distance pilot can see) decreases.
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A line with a slope of -10 passes through the points of (10, -7) and (9,j) what is the value of j?
CaHeK987 [17]
So, using our given information, we have a line of the equation y+7=-10(x-10), or y=-10x+93. Plugging in our value 9 for x, we get j = -10(9)+93 = 3.

j=3
7 0
3 years ago
In the diagram below, KL = 12 and LM = 8. Which additional facts would guarantee that JKLM is a parallelogram? Check all that ap
salantis [7]
I don't know the last point, but I'm going to assume it's N.
MN = 12 and KN = 8.
That would make this a rectangle.
All angles add up to 360.

4 0
3 years ago
Read 2 more answers
What is 9 3/10-1 7/10
OlgaM077 [116]
9 3/10- 1 7/10
8 13/10 - 1 7/10
7 6/10
7 3/5
8 0
3 years ago
Read 2 more answers
GET BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION!
Tresset [83]

Interpreting the inequality, it is found that the correct option is given by F.

------------------

  • The first equation is of the line.
  • The equal sign is present in the inequality, which means that the line is not dashed, which removes option G.

In standard form, the equation of the line is:

x + 2y = 6

2y = 6 - x

y = -0.5x + 2

Thus it is a decreasing line, which removes options J.

  • We are interested in the region on the plane below the line, that is, less than the line, which removes option H.

------------------

  • As for the second equation, the normalized equation is:

3x^2 + 3y^2 = 12

3(x^2 + y^2) = 12

x^2 + y^2 = 4

  • Thus, a circle centered at the origin and with radius 2.
  • Now, we have to check if the line x + 2y - 6 = 0, with coefficients a = 1, b = 2, c = -6, intersects the circle, of centre x = 0, y = 0
  • First, we find the following distance:

d = \sqrt{\frac{|ax + by + c|}{a^2 + b^2}}

  • Considering the coefficients of the line and the center of the circle.

d = \sqrt{\frac{|1(0) + 2(0) - 6|}{1^2 + 2^2}} = \sqrt{\frac{6}{5}} = 1.1

  • This distance is less than the radius, thus, the line intersects the circle, which removes option K, and states that the correct option is given by F.

A similar problem is given at brainly.com/question/16505684

3 0
3 years ago
129,543 rounded to the nearest ten thousand
Ksju [112]
130,000 129,543 is rounded up because the thousands place is a 9
5 0
3 years ago
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