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RUDIKE [14]
3 years ago
6

I need help simpifying 5x-2/4-25x^2

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

Answer:

−25x^2+5x−1/2

Step-by-step explanation:

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What is n? 12^2+n^2=(n+2)^2
Law Incorporation [45]

Answer:

n=35

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable

4 0
3 years ago
5. Find the value of x.<br> A. 55<br> B. 21<br> C. 12<br> D. 22<br> 3x -30
Irina-Kira [14]

Answer:

A is most reasonable

Step-by-step explanation:

The answer from that is -90 or 60, 55 is closest to 60

5 0
2 years ago
How can I solve this quadratic using the square root properly?
Citrus2011 [14]

Answer:

x = <u>+</u>3

Step-by-step explanation:

4x² = 36

sqareroot both side we get,

√4x² = √36

2x = 6

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x = <u>+</u>3

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<u>-TheUnknown</u><u>S</u><u>cientist</u>

7 0
2 years ago
Read 2 more answers
How do you write in words 4.110 and 4.10?
ohaa [14]

The <em>correct answers</em> are:

"Four and 11 hundredths" or "four and one hundred ten thousandths"; and

"Four and ten hundredths" or "four and one tenth."

Explanation:

In the first decimal, the digit 4 is in front of the decimal. This is read "Four and". After the decimal, we have 110. We look at the last place, digit, 0. Going by our place value, this is in the thousandths place. We read the block of digits 110 as "one hundred ten" and it is "thousandths." This makes the number "four and one hundred ten thousandths."

Alternatively, if we drop the zero, we would have 4.11. It is still "four and"; this time the last digit is 1, and it is in the hundredths place. 11 is read as "eleven", so this would be "four and eleven hundredths."

For the second number, 4.10, we have a 4 in front of the decimal, so we again have "four and". Our last digit is 0, and it is in the hundredths place; 10 is read "ten", so we have "four and ten hundredths."

Alternatively, if we drop the zero, we have 4.1. This is still "four and"; the 1 is now our last digit, and it is in the tenths place, so we have "four and one tenth."

8 0
3 years ago
Read 2 more answers
Use the distributive property to express 16+48
Kaylis [27]
\underline{\underline{\boxed{16+48 = 64}}}
5 0
3 years ago
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