All categories

3 years ago

What should be done to solve the following equation? (7.5)x = 45

Mathematics

2 answers:

Ymorist [56]3 years ago

8 0

Divide each side by 7.5 .

45 divided by 7.5 is 6 .

X equals 6

Tema [17]3 years ago

4 0

Divide each side by 7.5

You might be interested in

A rectangle has an area of (12m-30n) square units. Its width is 6 units. Factor the expression for the area to find an expressio

garik1379 [7]

Answer: 2m - 5n

<u>Explanation:</u>

Using long division

6 ) 12m - 30n

width*length = area

6(2m - 5n) = 12m - 30n

5 0

3 years ago

I'm thinking of two numbers. The first plus twice the second equals 11. Twice the first plus three times the second equals 50. W

valentinak56 [21]

2x + 4y - 2x - 3y = 22 - 50

y = -28

substitute into the 1st equation to find x

3 0

3 years ago

Which equations represent the line that is perpendicular to the line 5x – 2y = -6 and passes through the point

natta225 [31]

Answer: 2x + 5y = - 10, Cy + 4 = (x-5)

Dy - 4 = (x+ 5)

Step-by-step explanation:

Equation of the line

5x - 2y = -6

Conditions for perpendicularity

m1 x m2 = -1

To get m1, rearrange the equation

2y = 5x + 6

y = 5x/2 + 3

n1 = 5/2 and m2 = -2/5

To get C

y = mx +c

-4 = -2 x 5/5 + C

-4 = -2 + C

C = -4 + 2

C = -2

To get the equation of the second line

y = -2x/5 - 2

Multiply through by 5

5y = -2x - 10

2x + 5y = 10.

4 0

3 years ago

Read 2 more answers

Find the minimum value of the function f(x)=x^2+5x-6

mash [69]

<h3><u>Explanation</u></h3>

Method 1 (Formula)

$\begin{cases}h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{2a} \end{cases}$

The vertex of Parabola is the maximum/minimum point depending on the value of a.

Find Vertex

<u>h-value</u>

$h = - \frac{5}{2(1)} \\ h = - \frac{5}{2}$

<u>k-value</u>

$k = \frac{4(1)( - 6) - {(5)}^{2} }{4(1)} \\ k = \frac{ - 24 - 25}{4} \\ k = \frac{ - 49}{4} \\ k = - \frac{49}{4}$

The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.

Method 2 (Derivative)

This is Calculus method. We simply differentiate the function then substitute y' = 0.

Differentiate Function

$f'(x) = 2 {x}^{2 - 1} + {5x}^{1 - 1} - 0 \\ f'(x) = 2x + 5$

Substitute f'(x) = 0

$0 = 2x + 5 \\ - 5 = 2x \\ - \frac{5}{2} = x$

Substitute x = -5/2 in the original equation.

$f(x) = {( - \frac{5}{2} )}^{2} + 5( - \frac{5}{2} ) - 6 \\ f(x) = \frac{25}{4} - \frac{25}{2} - 6 \\ f(x) = \frac{25}{4} - \frac{50}{4} - \frac{24}{4} \\ f(x) = \frac{25}{4} - \frac{74}{4} \\ f(x) = - \frac{49}{4}$

<h3><u>Answer</u><u /></h3>

<u> $\sf{the \: \: minimum \: \: value \: \: is \: \: - \frac{49}{4} \: \: at \: \: x = - \frac{5}{2} }$ </u>

4 0

3 years ago

Solve for x.<br> \12x + 3<br> 13x + 2<br> x = [?]

Vsevolod [243]

Answer:

x=7

Step-by-step explanation:

25x+5=180

-5 -5

25x=175

/25 /25

3 0

2 years ago

Read 2 more answers