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3 years ago

What should be done to solve the following equation? (7.5)x = 45

Mathematics

2 answers:

Ymorist [56]3 years ago

8 0

Divide each side by 7.5 .

45 divided by 7.5 is 6 .

X equals 6

Tema [17]3 years ago

4 0

Divide each side by 7.5

You might be interested in

Can someone help with problems fivethroughseven

frutty [35]

Answer:

5) 15120

6) 11880

7) 336

Step-by-step explanation:

The formula for permutation where mPn is m!/(m-n)!

Applying this to question 5, we get 9!/4!, which is 15120.

For question 6, we get 12!/8!, which is 11880.

For question 7, we get 8!/5!, which is 336.

5 0

2 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .

You scored 24 on Exam A. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 20.1}{5.1}$

$Z = 0.76$

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that $\mu = 1031, \sigma = 215$ .

You scored 1167 on Exam B, s:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1167 - 1031}{215}$

$Z = 0.632$

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0

3 years ago

1. If the amount of fruit decreased by 35%, what percent of the original amount do you have?

katovenus [111]

Answer:

65% of the original amount.

Explanation:

Let's say that the original amount is 100%; therefore, if we subtract 35% from the original amount we have

$100\%-35\%$ $=65\%$

Hence, if the amount of fruit decreased by 35%, then we have 65% of the original amount left.

6 0

1 year ago

All questions to be solved using linear combination.

monitta

1)
I:x-y=-7
II:x+y=7

add both equations together to eliminate y:
x-y+(x+y)=-7+7
2x=0
x=0

insert x=0 into II:
0+y=7
y=7

the solution is (0,7)

2)
I: 3x+y=4
II: 2x+y=5

add I+(-1*II) together to eliminate y:
3x+y+(-2x-y)=4+(-5)
x=-1

insert x=-1 into I:
3*-1+y=4
y=7

the solution is (-1,7)

3)

I: 2e-3f=-9
II: e+3f=18

add both equations together to eliminate f:
2e-3f+(e+3f)=-9+18
3e=9
e=3

insert e=3 into I:
2*3-3f=-9
-3f=-9-6
-3f=-15
3f=15
f=5

the solution is (3,5)

4)
I: 3d-e=7
II: d+e=5

add both equations together to eliminate e:
3d-e+(d+e)=7+5
4d=12
d=3

insert d=3 into II:
3+e=5
e=2

the solution is (3,2)

5)
I: 8x+y=14
II: 3x+y=4

add I+(-1*II) together to eliminate y
8x+y+(-3x-y)=14-4
5x=10
x=2

insert x=2 into II:
3*2+y=4
y=4-6
y=-2

the solution is (2,-2)

8 0

3 years ago

Tind the variable of y x=3y

Morgarella [4.7K]

x=3y

Switch sides

3y=X

Divide 3 both sides to get

T= x/3

7 0

3 years ago