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evablogger [386]
3 years ago
14

a school cafeteria is considering new menu options. the manager puts a comment box jn the cafeteria where students can anonymous

ly submit their choices. is this a representative sample? explain why or why not
Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:

No, it is not a representative sample

Step-by-step explanation:

The sampling technique used above is more of a random sampling than a representative sampling. Reason is that;

A representative sample is referred to as a group or set selected from a larger population that satisfactorily represent the population in study in accordance to whatever criteria is under study.

The criteria could be age, sex, class, etc.

Another reason why it can't be considered as a representative sample is that, using representative sampling makes sure that all relevant types of people are included in your sample and that the right mix of people are interviewed.

In the question above, anybody can submit his or choice and number of submissions is not limited.

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andriy [413]

You forgot to include the options. This might help, though.

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3 years ago
Twenty-five percent of the students had forgotten the year of the Declaration of Independence. If 57 students had not forgotten,
Phantasy [73]

Answer:

76,

Step-by-step explanation:

If you divide 57 by 3, you get 19. If you times 19 by 4 that is the total number of students there were in all.

4 0
3 years ago
Perform the indicated operation.(4r/r+3) - (5/r)
Aleks [24]

Answer:

4r² - 5r - 15 / r(r+3)

Step-by-step explanation:

To solve this problem, we will proceed the following way, writing down the common multiple of the denominators.

\frac{4r}{r+3} -\frac{5}{r} =\frac{4r(r)-5(r+3)}{r(r+3)} =\frac{4r^{2}-5r-15 }{r(r+3)}

Thus, the answer is 4r² - 5r - 15 / r(r+3)

7 0
4 years ago
A line includes the points (4,5) and (1,-4). what is its equation in slope-intercept form
velikii [3]
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6 0
4 years ago
2sec^2x - secx - 1 = 0
Ivenika [448]
What are you trying to do here?
Solve the graph, or make it appear as something else?

First, we're going to take one sec (x) out so that we get:
sec (x) (2sec (x) -1 -1) = 0

sec (x) (2sec (x) -2) = 0


Then we're going to separate the two to find the zeros of each because anything time 0 is zero.

sec(x) = 0

2sec (x) - 2 = 0

Now, let's simplify the second one as the first one is already.

Add 2 to both sides:

2sec (x) = 2

Divide by 3 on both sides:

sec (x) = 1


I forgot my unit circle, so you'd have to do that by yourself. Hopefully, I helped a bit though!
8 0
3 years ago
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