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kirill [66]
3 years ago
10

The system of equations has how many solutions? y=-3/2x+5 and y=-3/2x-3

Mathematics
1 answer:
mixas84 [53]3 years ago
8 0
Here the right side of the 2 equations (which are different)   both equal y
so 0 solutions
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What x^2 x 3x + 1000x please help
Kruka [31]

Answer: x * (x + 1003)

Step-by-step explanation:

x^2 x 3x + 1000x

x^2 + 1003x

x * (x + 1003)

8 0
2 years ago
What is 5(n-1)=2(n-4)-6
Shalnov [3]

Answer:

Step-by-step explanation

6n - 6 = 2 (n+1)

Simplify 2 (n+1)

6n - 6= 2n +2

Move all terms related to n to the left side of the equation

4n -6 =2

Move all terms not related to n to the right side of the equation

4n =8

Divide each term by 4 then simplify

n=2  

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35,000,000 what is the order of magnitude of this number
uysha [10]
The anwser is 7 your welcome!
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What times 27equals 216
svlad2 [7]
27 time 8 equals 216
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216 divided by 27 equals 8
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I have nooooo clue, please help
Aleksandr-060686 [28]

Answer:

case a) x^{2}=3y ----> open up

case b) x^{2}=-10y ----> open down

case c) y^{2}=-2x ----> open left

case d) y^{2}=6x ----> open right

Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

y=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

x=a(y-k)^{2}+h

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

x^{2}=3y

so

y=(1/3)x^{2}

a=(1/3)

so

a>0

therefore

The parabola open up

case b) we have

x^{2}=-10y

so

y=-(1/10)x^{2}

a=-(1/10)

a

therefore

The parabola open down

case c) we have

y^{2}=-2x

so

x=-(1/2)y^{2}

a=-(1/2)

a

therefore

The parabola open to the left

case d) we have

y^{2}=6x

so

x=(1/6)y^{2}

a=(1/6)

a>0

therefore

The parabola open to the right

3 0
2 years ago
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