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ArbitrLikvidat [17]

3 years ago

13

Part A

1 answer:

Simora [160]3 years ago

3 0

I forgot how to do this in middle school_

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Express as a single power of 2

den301095 [7]

When you multiply powers, they add, and when you divide them they subtract.
So I would first add the 2^a + 2^b +2^c to get 2^(a+b+c)
Then, divide by 2^(a+b). Because when you divide powers they subtract, you will be taking away the (a+b) from the (a+b+c) and you will be left with c on its own.
The answer is 2^c

6 0

3 years ago

How do I Graph y= –73x+2 .

Romashka-Z-Leto [24]

Answer:

See attachment

Step-by-step explanation:

You can obtain any two points on the graph of $y=-73x+2$ and use it to draw its graph.

When x=0, $y=-73*0+2=2$

So you plot (0,2)

When x=1, $y=-73*1+2=-71$

You again plot (1,-71).

With a straight edge you can now draw a straight line through the two points.

See attachment

4 0

3 years ago

What is the answer?????/

SCORPION-xisa [38]

The questions is, when z=9, 3z = ? When you multiply 3*9, you get 27

3 0

3 years ago

The triangle on the grid will be translated two units left. On a coordinate plane, triangle A B C has points (negative 1, negati

nignag [31]

Answer:

Option B.

Step-by-step explanation:

The given vertices of triangle ABC are (-1, -1), (-1, -5) and (0.5, -5).

We need to find the coordinates of triangle when it is translated two units left.

So, the rule of translation is

$(x,y)\rightarrow (x-2,y)$

Using this rule, we get

$A(-1,-1)\rightarrow A'(-1-2,-1)=A'(-3,-1)$

$B(-1,-5)\rightarrow B'(-1-2,-5)=B'(-3,-5)$

$C(0.5,-5)\rightarrow C'(0.5-2,-5)=C'(-1.5,-5)$

The vertices of triangle A'B'C' are A'(-3,-1), B'(-3,-5) and C'(-1.5,-5).

Therefore, the correct option is B.

8 0

2 years ago

Read 2 more answers

X + 5y = 28<br> - x - 2y = -13

bazaltina [42]

Answer:

x=3

y=5

Step-by-step explanation:

x+5y=28 (i)

-x-2y=-13. (ii)

add equation 2 from equation 1

x+5y=28

-x-2y=-13

3y=15

y=5

put the value of y in equation 1

x+5y=28

x+5*5=28

x+25=28

x=28-25

x=3

8 0

3 years ago