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3 years ago

Subtract 5a-6b+7c from 13a-4b+8c

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

Answer:

im not sure but i think the anwser is its self dont take my anwser its garbadge

Step-by-step explanation:

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A B C D ? PLS HELP THESE ARE MY FINALS!!

aksik [14]

Answer:

the answer is A

Step-by-step explanation:

5 0

3 years ago

Question 5 of 10<br> Solve the rational equation:<br> 4x/x+5 = x/x+4

beks73 [17]

Answer:

$x = 0$ or $x = -\dfrac{11}{3}$

Step-by-step explanation:

I assume the denominators are x + 5 and x + 4 although that is not what you wrote.

$\dfrac{4x}{x+5} = \dfrac{x}{x+4}$

$(x + 4)(x + 5)\times \dfrac{4x}{x+5} = (x + 4)(x + 5) \times \dfrac{x}{x+4}$

$(x + 4)(4x) = (x + 5)(x)$

$4x^2 + 16x = x^2 + 5x$

$3x^2 + 11x = 0$

$x(3x + 11) = 0$

$x = 0$ or $3x + 11 = 0$

$x = 0$ or $3x = -11$

$x = 0$ or $x = -\dfrac{11}{3}$

5 0

2 years ago

Find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)

Murljashka [212]

Answer:

Equation of circle is: $\mathbf{(x+1)^2+(y-5)^2=28.94}$

Step-by-step explanation:

We need to find an equation of the circle that satisfies the stated conditions. (Give your answer in standard notation.)

Endpoints of a diameter A(−6, 3) and B(4, 7)

The general equation of circle is: $(x-h)^2+(y-k)^2=r^2$

Where r is radius and (h,k) is centre of circle.

Finding centre of circle

The midpoint of diameter is centre of circle.

So, finding midpoint of A(−6, 3) and B(4, 7)

The formula used is: $Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$

We have x_1=-6, y_1=3, x_2=4, y_2=7

$Midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )\\Midpoint=(\frac{-6+4}{2} ,\frac{3+7}{2} )\\Midpoint=(\frac{-2}{2} ,\frac{10}{2} )\\Midpoint=(-1 ,5)$

So, we get Midpoint (x,y)=(-1,5)

Finding radius of circle

Radius of circle can be found by first finding diameter using distance formula and then divide it by 2.

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\Distance=\sqrt{(4-(-6))^2+(7-3)^2} \\Distance=\sqrt{(4+6)^2+(7-3)^2} \\Distance=\sqrt{(10)^2+(4)^2} \\Distance=\sqrt{100+16}\\Distance=\sqrt{116}\\Distance = 10.77$