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natali 33 [55]
3 years ago
10

What are Factors and Primes?

Mathematics
1 answer:
12345 [234]3 years ago
3 0
A factor of a number is a number you multiply by another factor to get a number. For example, a factor of 6 is 3 because 3 × 2 = 6, and a factor of 12 is 4 because 4 × 3 = 12. A prime number is a number that only has two factors, 1 and itself, which every number has. Examples of prime numbers are 13, 5, 47, 93, etc. Let me know if you still don't get it!
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adoni [48]

Answer:

what topic is this please

8 0
3 years ago
Elaine had 5/8 of a pizza left after lunch. She told 5 of her friends that they could share the rest. What fraction of the pizza
Oduvanchick [21]

Answer:

1/8

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
(c) what is the probability that diameter is within 2 mm of the mean diameter? (round your answer to three decimal places.)
postnew [5]
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7 0
3 years ago
The sum of 4 consecutive integers is 434. What is the 4 integers?
gavmur [86]
Answer: 107, 108, 109 & 110

Explaination: Divide 434 by 4.

I hope this has helped! Brainliest if you will :)
3 0
3 years ago
Determine whether each of the binary relation R defined on the given sets A is reflexive, symmetric, antisymmetric, or transitiv
ki77a [65]

Answer:

In explanation

Please let me know if something doesn't make sense.

Step-by-step explanation:

a)

*This relation is not reflexive.

0 is an integer and (0,0) is not in the relation because 0(0)>0 is not true.

*This relation is symmetric because if a(b)>0 then b(a)>0 since multiplication is commutative.

*This relation is transitive.

Assume a(b)>0 and b(c)>0.

Note: This means not a,b, or c can be zero.

Therefore we have abbc>0.

Since b^2 is positive then ac is positive.

Since a(c)>0, then (a,c) is in R provided (a,b) and (b,c) is in R.

*The relation is not antisymmretric.

(3,2) and (2,3) are in R but 3 doesn't equal 2.

b)

*This relation is reflective.

Since a^2=a^2 for any a, then (a,a) is in R.

*The relation is symmetric.

If a^2=b^2, then b^2=a^2.

*The relation is transitive.

If a^2=b^2 and b^2=c^2, then a^2=c^2.

*The relation is not antisymmretric.

(1,-1) and (-1,1) is in the relation but-1 doesn't equal 1.

c)

*The relation is reflexive.

a/a=1 for any a in the naturals.

*The relation is not symmetric.

Wile 4/2 is an integer, 2/4 is not.

*The relation is transitive.

If a/b=z and b/c=y where z and y are integers, then a=bz and b=cy.

This means a=cyz. This implies a/c=yz.

Since the product of integers is an integer, then (a,c) is in the relation provided (a,b) and (b,c) are in the relation.

*The relation is antisymmretric.

Assume (a,b) is an R. (Note: a,b are natural numbers.) This means a/b is an integer. This also means a is either greater than or equal to b. If b is less than a, then (b,a) is not in R. If a=b, then (b,a) is in R. (Note: b/a=1 since b=a)

6 0
2 years ago
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