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3 years ago

True or false, cloud storage does not require internet access?

Computers and Technology

1 answer:

Dmitry_Shevchenko [17]3 years ago

3 0

False, the storage is being accessed from the cloud which can only be accessed through an internet connection.

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Allie needs to add a long row of numbers. She should enter a

ikadub [295]

I believer the answere is a formula hope this helped

8 0

3 years ago

Read 2 more answers

Write code that prints: usernum ... 2 1 blastoff! your code should contain a for loop. print a newline after each number and aft

Svetradugi [14.3K]

You never said what language so I used C

#include <stdio.h>

int main () {

int a;

for( a = 3; a > 0; a-- ){

printf("%i \n", a); }

printf(" Blast OFF !!!\n");

return 0;

}

4 0

3 years ago

Write the Number class that can be used to test if the number is odd, even, and perfect. A perfect number is any number that is

egoroff_w [7]

Answer:

Explanation:

The following code is written in Python. It creates a class that takes in one ArrayList parameter and loops through it and calls two functions that check if the numbers are Perfect, Odd, or Even. Then it goes counting each and printing the final results to the screen.

class NumberAnalyzer:

def __init__(self, myArray):

perfect = 0

odd = 0

even = 0

for element in myArray:

if self.isPerfect(element) == True:

perfect += 1

else:

if self.isEven(element) == True:

even += 1

else:

odd += 1

print("# of Perfect elements: " + str(perfect))

print("# of Even elements: " + str(even))

print("# of Odd elements: " + str(odd))

def isPerfect(self, number):

sum = 1

i = 2

while i * i <= number:

if number % i == 0:

sum = sum + i + number / i

i += 1

if number == sum:

return True

else:

return False

def isEven(self, number):

if (number % 2) == 0:

return True

else:

return False

6 0

3 years ago

How many possible password of length four to eight symbols can be formed using English alphabets both upper and lower case (A-Z

Fynjy0 [20]

Answer:

In a password, symbol/characters can be repeated. first calculate the total

symbols which can be used in a password.

So there are total 26(A-Z),26(a-z),10(0-9) and 2(_,$) symbols.

that is equal to 26+26+10+2=64.

Total number of password of length 4:

here at each place can filled in total number of symbols i.e 64 way for each

place.Then total number of possible password is:

64*64*64*64=16777216

Total number of password of length 5:

here at each place can filled in total number of symbols i.e 64 way for each

place.Then total number of possible password is:

64*64*64*64*64=1073741824

Similarly,

Total number of password of length 6:

64*64*64*64*64*64=68719476736

Total number of password of length 7:

64*64*64*64*64*64*64=4398046511104

Total number of password of length 8:

64*64*64*64*64*64*64=281474976710656

Hence the total number of password possible is:285,942,833,217,536

7 0

4 years ago

Azzam is reviewing a paper he just wrote about kinetic friction for his physics class. On the third page, he realizes that every

bogdanovich [222]

Answer: Azzam used the tool while he was on the third page

Explanation:

The most likely the reason why the phrase was not fixed is because Azzam used the tool while he was on the third page.

This can be infered from the information given when we're told that he uses the Find and Replace tool and clicks on "Replace All" to fix the issue with regards to the error that he made and thus was done from the third page. Therefore, the tool might not have worked for the first page.

4 0

3 years ago