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katovenus [111]
4 years ago
5

____________________ parameters are useful in three situations: • When the value of the actual parameter needs to be changed • W

hen you want to return more than one value from a function • When passing the address would save memory space and time relative to copying a large amount of data
Computers and Technology
1 answer:
jenyasd209 [6]4 years ago
8 0

Answer:

The correct word for the blank space is: Reference.

Explanation:

In C++, Reference Parameter is a type of parameter that does not need additional storage since it represents an already existing function.  The function has the characteristic of passing more than one (1) variable. Reference parameters are also used to edit the existing parameter or when referencing a function saves storage compared to creating a new function.

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Write code to complete print_factorial()'s recursive case. sample output if user_val is 5: 5! = 5 * 4 * 3 * 2 * 1 = 120
maxonik [38]
```
#!/usr/local/bin/python3


import sys

def print_factorial( user_val ):
    if( user_val < 1 ):
        return( 1 )
    else:
        return( print_factorial( user_val - 1 ) * user_val )


if( __name__ == "__main__" ):
    if( len( sys.argv ) == 2 ):
        print( print_factorial( int ( sys.argv[ 1 ] ) ) )
    else:
        sys.stderr.write( "usage: %s <integer>\n" % sys.argv[ 0 ] )

    exit( 0 )
```

5 0
3 years ago
What is the datapath of add instruction?
alina1380 [7]

i dont have enough information to awnser this

6 0
3 years ago
What are the benefits of using an ordered list vs. an unordered list? What are the costs?
Rashid [163]

Answer:

The main benefit of the ordered list is that you can apply Binary Search( O( n log n) ) to search the elements. Instead of an unordered list, you need to go through the entire list to do the search( O(n) ).

The main cost of the ordered list is that every time you insert into a sorted list, you need to do comparisons to find where to place the element( O( n log n) ). But, every time you insert into an unsorted, you don't need to find where to place the element in the list ( O(1) ). Another cost for an ordered list is where you need to delete an element, you have an extra cost rearranging the list to maintain the order.

6 0
3 years ago
Assume that you have an ArrayList variable named a containing 4 elements, and an object named element that is the correct type t
jonny [76]

Answer:

Option (4) is the correct answer.

Explanation:

In Java programming language ,array collection starts from 0 index location and ends in a size-1 index location. So to access the last elements the user needs to use a[Size-1] statement. so to modify the value of the last location of the array the user needs to use "a[size-1]= element;".

But when the user wants to add some new value to the end of the array list collection then he needs to use the statement--

a.add(element); //where add is a function, element is a value and a is a array list object.

Another option is invalid because--

  • Option 1 is not the correct because "a[3]=element;" modify the value of the 3rd element of the array.
  • Option 2 gives a compile-time error because add functions bracts are not closed.
  • Option 3 gives the error because a[4] gives the location of the 5th element of the array but the above question says that a is defined with 4 elements.
7 0
3 years ago
What considerations should you make when deciding on the size of a table?
Kisachek [45]

Answer:

You should consider the number of cells needed for data, labels, titles, and formulas.

Explanation:

4 0
3 years ago
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