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scoundrel [369]
4 years ago
10

After a dilation with a center of (0, 0), a point was mapped as (4, –6) → (12, y). A student determined y to be –2. Evaluate the

student's answer
Mathematics
1 answer:
crimeas [40]4 years ago
8 0
That would not be right because 4 times 3 equals 12 and -6 times 3 equals -18.
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So I don't know what 5*7 is because it confusing
RideAnS [48]

Answer:

35/16

Explanation:

(5*7)/2^4

= 35/2^4

= 35/16

Note:

Please mark as brainliest! <3

3 0
3 years ago
Read 2 more answers
I don't have much but 25 points and brainliest pls :/
GaryK [48]

Answer:

x = −5.5 i think

Step-by-step explanation:

Good Luck!

8 0
3 years ago
2x + 3 + 4x + 8 = 3x - 10
vodomira [7]

\text {Hello! Let's solve this Equation!}

\text {Your First Step is to Simplify the Equation:}

\text {(2x+4x)+(8+3)}

\text {6x+11=3x-10}

\text {The Next Step is to Subtract 3x:}

\text {6x+11-3x=3x-10-3x}\\\text {3x+11=-10}

\text {Next Step is to Subtract 11:}

\text {Q: Why Subtract 11?}

\text {A: So they cancel out. We cross them out once we subtract.}

\text {3x+11-11=-10-11}\\\text {3x=-21}

\text {The Final Step is to Divide 3:}

\text {3x/3=-21/3}

\text {Your Answer will be}

\fbox {x=-7}

\text {Best of Luck!}

\text {-LimitedX}

8 0
3 years ago
Solve for x ~<br><img src="https://tex.z-dn.net/?f=6x%20-%2036%20%3D%2012" id="TexFormula1" title="6x - 36 = 12" alt="6x - 36 =
Shtirlitz [24]

\large \tt \:  \:  \:  \:  \:  \: ⇝ \: 6x - 36 = 12

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\large \tt \:  \:  \:  \:  \:  \: ⇝ 6x = 12 + 36

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\large \tt \:  \:  \:  \:  \:  \: ⇝ 6x = 48

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\large \tt \:  \:  \:  \:  \:  \: ⇝ \:x =   \cancel\frac{48}{6}

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\boxed{ \large \bf \color{purple}  \:  \:  \:  \:  \: ⇝ \:x = 8}

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-_- Hope Helps!¡!¡!¡!¡!

7 0
2 years ago
Read 2 more answers
Suppose b is any integer. If b mod 12 = 5, then 7b mod 12
Rzqust [24]

The result follows directly from properties of modular arithmetic:

b\equiv5\pmod{12}\implies 7b\equiv35\equiv-1\equiv\boxed{11}\pmod{12}

That is,

b\equiv5\pmod{12}

means we can write b=12n+5 for some integer n. Then

7b=7(12n+5)=12(7n)+35

and taken mod 12, the first term goes away, so

7b\equiv35\pmod{12}

etc

8 0
3 years ago
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