12 is to 56 is the correct answer or just option D lol :)
k/9-1=12
We move all terms to the left:
k/9-1-(12)=0
We add all the numbers together, and all the variables
k/9-13=0
We multiply all the terms by the denominator
k-13*9=0
We add all the numbers together, and all the variables
k-117=0
We move all terms containing k to the left, all other terms to the right
k=117
Answer:
The probability that a randomly selected student didn’t take economics but did take statistics is 13%.
Step-by-step explanation:
Let the event that a student offers Economics be E.
The event that a student does NOT offer Economics is E'.
Let the event that a student offers Statistics be S.
The event that a student does NOT offer Statistics be S'.
P(E) = 13.5% = 0.135
P(S) = 24.7% = 0.247
P(E n S) = 11.7% = 0.117
Find the probability that a randomly selected student didn’t take economics but did take statistics
This probability = P(E' n S)
Since E and E' are mutually exclusive events,
P(S) = P(E' n S) + P(E n S)
P(E' n S) = P(S) - P(E n S)
P(E' n S) = 0.247 - 0.117 = 0.13 = 13%
Hope this Helps!!!
Answer:
Step-by-step explanation:
By the distributive property of multiplication, 2x(x-4) = 2x^2 - 8x. This could be re-written as 2(x^2 - 8).
