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3 years ago

√7 is between what two consecutive integers?

Mathematics

1 answer:

bulgar [2K]3 years ago

7 0

Answer: √7 is between 2 and 3

Step-by-step explanation:

The next lower number that is a perfect square is 4, the next higher perfect square is 9. Take the roots of those two numbers to find the integers you are looking for.

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The proportion of students who own a cell phone on college campuses across the country has increased tremendously over the past

galina1969 [7]

Complete Question

The complete question is shown on the uploaded image

Answer:

1 ) The correct option B

2) The correct option is C

3) The correct option is C

4) The correct option is C

Step-by-step explanation:

From the question we are told that

The proportion that own a cell phone is $p = 0.90$

The sample size is n = 15

Generally the appropriate distribution for X is mathematically represented as

$X \ is \ B( n , p )$

$X \ is \ B( 15 , 0.90 )$

Generally the number students that own a cell phone in a simple random sample of 15 students is mathematically represented as

$\mu = n * p$

$\mu = 15 * 0.90$

$\mu = 13.5$

Generally the standard deviation of the number of students who own a cell phone in a simple random sample of 15 students is mathematically represented as

$\sigma = \sqrt{ n * p * q }$

Where q is mathematically evaluated as

$q = 1- p$

$q = 1- 0.90$

$q = 0.10$

$\sigma = \sqrt{ 15 * 0.90 * 0.10 }$

$\sigma = 1.16$

Generally the probability that all students in a simple random sample of 15 students own a cell phone is mathematically represented as

$P(X = 15) = \left 15} \atop {}} \right.C_{15} * p^{15} * q^{15 - 15}$

$P(X = 15) = \left 15} \atop {}} \right.C_{15} * (0.90)^{15} * (0.10 )^{15 - 15}$

From the combination calculator is $\left 15} \atop {}} \right.C_{15} = 1$

$P(X = 15) = 1 * 0.205891 * 1$

$P(X = 15) = 0.206$

7 0

3 years ago

Find DY divided by DX by implicit differentiation y=sinxy

amm1812

Answer:

Step-by-step explanation:

$y = sin(xy)\\\frac{d}{dx}y=cos(xy)(\frac{d}{dx}(xy))\\ \frac{d}{dx}y = cos(xy)(y + x*\frac{d}{dx}y)\\ write \: \frac{d}{dx}y \: as\:y'\\y' = cos(xy)(y+xy')\\y' = ycos(xy) + xy'cos(xy) \\y'-xy'cos(xy) = ycos(xy)\\y'(1-xcos(xy)) = ycos(xy)\\\\y' = \frac{ycos(xy)}{1-xcos(xy)}$